Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
135 comments Page 2 of 14.
Ahmed Raafat said:
2 years ago
Run rate = number of runs/number of overs.
(15)
ANVITHA said:
4 years ago
Runs scored= run rate*overs.
= 3.2*10,
= 32.
In remaining 40 overs they score 250 runs.
Runs scored=run rate * overs.
250 = run rate * 40.
Run rate = 250/40.
= 6.25.
= 3.2*10,
= 32.
In remaining 40 overs they score 250 runs.
Runs scored=run rate * overs.
250 = run rate * 40.
Run rate = 250/40.
= 6.25.
(111)
Jyothis said:
4 years ago
Assume run rate as average,
Then, Avg of first 10 overs = 3.2.
Avg(10) = total runs for 10overs/no.of overs.
3.2=total runs/10.
Total runs for 10 overs = 3.2 * 10 = 32,
Remaining runs=282-32 = 250,
Avg runs remaining 40 overs = 250/40 = 6.25.
Then, Avg of first 10 overs = 3.2.
Avg(10) = total runs for 10overs/no.of overs.
3.2=total runs/10.
Total runs for 10 overs = 3.2 * 10 = 32,
Remaining runs=282-32 = 250,
Avg runs remaining 40 overs = 250/40 = 6.25.
(36)
Manalan said:
5 years ago
First 10 over,
3.2 = 10 * 3.2 = 32runs.
40 overs is 282 = 282-32.
= 250.
250 ÷ 40 = 6.25,
6.25.
3.2 = 10 * 3.2 = 32runs.
40 overs is 282 = 282-32.
= 250.
250 ÷ 40 = 6.25,
6.25.
(9)
Balaji said:
5 years ago
First 10 overs run rate 3.2=3.2 * 10 = 32.
Next, 40 overs is 282 = 282 - 32 = 250.
250 ÷ 40 overs = 6.25.
So, the answer is 6.25.
Next, 40 overs is 282 = 282 - 32 = 250.
250 ÷ 40 overs = 6.25.
So, the answer is 6.25.
(6)
Masthan said:
5 years ago
10 * 3.2 = 32
40 * X = 282
=> 282 - 32 = 250.
40X = 250.
X = 250/40.
X = 6.25.
40 * X = 282
=> 282 - 32 = 250.
40X = 250.
X = 250/40.
X = 6.25.
(9)
Suchi said:
5 years ago
Use the Average formula :
Average = sum of observations/number of observations.
For first 10 overs :
3.2 = Sum/10 --> Sum = 32--> Run in first 10 overs.
The total score is 282. First 10 overs, we scored 32 runs. So, remaining (282-32) runs=250 runs in 40 overs.
Applying the formula:
Average = sum of observations/number of observations.
Average= 250/40 = 6.25.
Average = sum of observations/number of observations.
For first 10 overs :
3.2 = Sum/10 --> Sum = 32--> Run in first 10 overs.
The total score is 282. First 10 overs, we scored 32 runs. So, remaining (282-32) runs=250 runs in 40 overs.
Applying the formula:
Average = sum of observations/number of observations.
Average= 250/40 = 6.25.
(14)
Shreya said:
5 years ago
In a cricket match, Ashwin scored 40perct. Of total run scored by his team & Arijit scored 140 run which is 200/9perct less than Ashwin's score, find total run scored by Ashwin's team, Anyone please answer it.
(3)
Rahul Vishwakarma said:
6 years ago
Left over = 40-10 = 30overs.
So, required run rate = (target /left over ) - current run rate.
= (282/30)- 3.2.
= 6.2.
So, required run rate = (target /left over ) - current run rate.
= (282/30)- 3.2.
= 6.2.
(2)
Ajay Kumar said:
6 years ago
The first 10 overs run rate is 3.2 which means score will be taken 32 runs per 10 overs.
Target is 282 then 282-32=250 remaining 40 overs runs.
Finally 250/40=6.25.
Target is 282 then 282-32=250 remaining 40 overs runs.
Finally 250/40=6.25.
(2)
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