# Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
6.25
6.5
6.75
7
Explanation:

 Required run rate = 282 - (3.2 x 10) = 250 = 6.25 40 40

Video Explanation: https://youtu.be/GhK9d8tcqvA

Discussion:
126 comments Page 1 of 13.

Aayush said:   10 years ago
@Gautam - Sorry to say but your solution is wrong.
@Aymen - The solution for your problem stated.

"The average of three numbers is 8, that of the first two is 11. Find the third number?please help me." is:

Let three numbers be x,y,z.
Average of first three numbers is 8.
Hence, x+y+z/3 = 8.
=> x+y+z = 24.....eq(1).

Average of first two numbers is = 11.
Hence, x+y/2 = 11.
=> x+y = 22....eq(2).

Now substitute eq(2) value in eq(1).
Thus, 22+z = 24.
=> z = 24-22 = 2.
:).

Sameer Rolekar said:   9 years ago
Note we have a formula => Runrate*Overs = Run Scored.

1st > we have given Runrate and overs, so we are calculating the run scored.

ie. 3.2*10 = ? (Run Scored) we get Run scored = 32.

2nd > we have to find the run scored in the remaining 40 overs so we subtract the run scored in the first 10 over from the Total score.

i.e. 282-32=250.

Now we have run scored=250 and overs=40, so we find will find the run rate.

i.e. Runrate*Overs = Run Scored.

Runrate*40 = 250.

(1)

RIDDHI said:   7 years ago
282 ie the target run.
10 over + 40 over = 50 over ie in 50 overs 282 should be made in order to win.
So run rate in 50 over needed is 282/50 = 5.64.

USING METHOD OF DEVATION.
3.2--5.64= --2.44*10 = --24.4......deviation for 10 overs (equ 1).
(Let X be avg for next 40 overs).
(X--5.64)*40 = 40X--225.6.......deviation for 40 overs.
(Equ 2)
Solving equ 1 and 2 we get,
40X--255.6--24.4 = 40X--250.
X = 250/40 = 6.25 run rate required in 40 overs.

@nikhil

First we have to find no of runs scored in first 10 overs, to calculate runs scored in 10 overs we have to do 3.2*10 (means runsscored=runrate*no of overs).we get 32runs which means they have scored 32 runs in first 10 overs. so 283-32=250 runs should be scored in next 40 overs.to find the runrate, runrate=250/40 (we have to divide no of required runs by no of overs left)

Suchi said:   4 years ago
Use the Average formula :

Average = sum of observations/number of observations.

For first 10 overs :
3.2 = Sum/10 --> Sum = 32--> Run in first 10 overs.
The total score is 282. First 10 overs, we scored 32 runs. So, remaining (282-32) runs=250 runs in 40 overs.

Applying the formula:

Average = sum of observations/number of observations.
Average= 250/40 = 6.25.
(13)

GANGARAJU T C said:   1 decade ago
First 10 overs Score = 10 overs x 3.2 Run Rate = 32 Runs.
Total targeted runs in 50 overs = 282 Runs
Required Runs to be scored in 40 overs = 250
Total 50 overs Runs(282 Runs)-First 10 overs runs Scored(32 Runs)
Required Run Rate in 40 overs = Required Runs/Remaining overs
= 250 Runs /40 overs
= 6.25
(1)

Siva said:   7 years ago
@Pranav.

Batsman scored 87 runs in his 17th innings as we all know that average is nothing but equal distribution.

So we can say that his increased average should be shared to every innings so 17*3=51 now we can clearly say that if he wants to increase his average he has to score more runs than the previous innings. so answer 87-17 * 3=> 87 - 51 = 36.

Brahmin Shrestha said:   6 years ago
Total over of match=10+40=50.
Total runs in 50 overs=282.
First 10 overs runs =3.2*10=32.
We have to calculate run rate of last 40 overs.
Now..run in 40 over= total run-10 over's run.
So, 282-32=250.

Run rate in 40 overs= run in 40 overs ÷overs.
=250÷40=6.25.

Hence, the required run rate in 40 is 6.25 answer.
(1)

Raja said:   5 years ago
First we have to calculate the last 40 overs run rate.

Total score =282 but already they are scored in first 10 overs score was(10 * 3.2=32),
For these, we are subtracting,
Total score -10 overs score then (282-32) = 250.
Then we have get the score of last 40 over the score was 250.
Total score scored by last 40 overs/ number of overs.
250/40 = 6.25.
(2)

@Colbie.

Use this formula to solve the problem:

Average = sum of runs/number of tests.

Given that, average on 4 tests is 80.

Hence, Sum of runs scored = 80 x 4 = 360.

To calculate the number of runs he needs in his fifth test to raise his average to 84 is,

84 = 360 + x / 5 (use the formula given above).

x = 420 - 360 = 60 (answer).