Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 2 of 14.
Nikhil said:
1 decade ago
Why you write 283- (3. 2*10)?
Deepa said:
1 decade ago
@nikhil
First we have to find no of runs scored in first 10 overs, to calculate runs scored in 10 overs we have to do 3.2*10 (means runsscored=runrate*no of overs).we get 32runs which means they have scored 32 runs in first 10 overs. so 283-32=250 runs should be scored in next 40 overs.to find the runrate, runrate=250/40 (we have to divide no of required runs by no of overs left)
First we have to find no of runs scored in first 10 overs, to calculate runs scored in 10 overs we have to do 3.2*10 (means runsscored=runrate*no of overs).we get 32runs which means they have scored 32 runs in first 10 overs. so 283-32=250 runs should be scored in next 40 overs.to find the runrate, runrate=250/40 (we have to divide no of required runs by no of overs left)
Swathy said:
1 decade ago
Excellent deepa and muhunthan.
Srinivas reddy said:
1 decade ago
First we calculate the total runs done in 10 overs by using run rate ie 10*3.2 (runs per over) = 32.
Remaining runs is 283-32 = 250.
The run rate required to achieve the target is 250 (required runs to do) /40 (remaining overs).
Remaining runs is 283-32 = 250.
The run rate required to achieve the target is 250 (required runs to do) /40 (remaining overs).
Gdged said:
1 decade ago
Why we are using this formula?
Vinoth M said:
1 decade ago
Formula is, average=sum of runs in each overs(s)/number of overs(n)
given n=10,average=3.2
Then,substitute values in formula,
->3.2=s/10
->s=32
in 10 overs total run is 32
target=282
Then in 40 overs thy need 250 runs
here n=40,s=250
percentage=s/n=250/40=6.25
So ans=6.25
given n=10,average=3.2
Then,substitute values in formula,
->3.2=s/10
->s=32
in 10 overs total run is 32
target=282
Then in 40 overs thy need 250 runs
here n=40,s=250
percentage=s/n=250/40=6.25
So ans=6.25
Kalaivani said:
1 decade ago
Why you write 283- (3. 2*10)?
Sathi said:
1 decade ago
@kalaivani,
We want to calculate how many runs needed for remaining 40 overs to find the run rate for remaining overs.
283 is total score req for 40 overs,10*3.2=32 runs scored in the first over
We want to calculate how many runs needed for remaining 40 overs to find the run rate for remaining overs.
283 is total score req for 40 overs,10*3.2=32 runs scored in the first over
Nayan das said:
1 decade ago
Very good explanation vinoth m, thanks.
Tanvir said:
1 decade ago
It may be like this:
Let the required run rate be x.
Then Run in 40 overs = 40x (Becoz run rate = run per over)
Run in 10 overs= 10x3.2 (It is given that run rate of 10 overs is 3.2)
We know we required to calculate the run rate for 282 runs.
Then according to question:
3.2x10+40x=282
32+40x=282
40x=250
x=250/40=6.25 ans
Let the required run rate be x.
Then Run in 40 overs = 40x (Becoz run rate = run per over)
Run in 10 overs= 10x3.2 (It is given that run rate of 10 overs is 3.2)
We know we required to calculate the run rate for 282 runs.
Then according to question:
3.2x10+40x=282
32+40x=282
40x=250
x=250/40=6.25 ans
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