Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 3 of 14.
Isha panchal said:
1 decade ago
Muhundhan sir thanks.
Nithinvino said:
1 decade ago
Thanks muhundan.
Tintu mathew said:
1 decade ago
The simple method is
total runs takes in 10 over=3.2*10=32
we know dat target is 282
so
32+40*x=282
from this we get required run rate.
total runs takes in 10 over=3.2*10=32
we know dat target is 282
so
32+40*x=282
from this we get required run rate.
Aymen said:
1 decade ago
Muhundan you are really very helpful.
How should I solve this.
The average of three numbers is 8, that of the first two is 11. Find the third number?plz help me.
How should I solve this.
The average of three numbers is 8, that of the first two is 11. Find the third number?plz help me.
GAUTAM said:
1 decade ago
THE AVERAGE OF THREE NO.IS
X+Y+Z/3=8
THE SUM OF FIRST TWO NO. IS 11,SO
(X+Y)+Z/3=8
11+Z/3=8
BY TRANSPOSITION
11+Z=3*8
11+Z=24
Z=24-11
Z=13
Z
X+Y+Z/3=8
THE SUM OF FIRST TWO NO. IS 11,SO
(X+Y)+Z/3=8
11+Z/3=8
BY TRANSPOSITION
11+Z=3*8
11+Z=24
Z=24-11
Z=13
Z
Arti said:
1 decade ago
Thanks muhundhan thats great.
Radhika said:
1 decade ago
Is there any formula?
Jay said:
1 decade ago
Thank you very much muhundhan. Simple answer to understand.
DKB said:
1 decade ago
Pratik and Muhundhan Thanks for simplifying the problem.
Maha said:
1 decade ago
Thanks vignesh mahesh.
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