Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 14 of 14.
Karthi said:
10 months ago
First 10 - run rate 3.2
3.2 = sum of runs/10
Sum = 3.2×10 = 32
40 over total runs 282.
So, 282 - 32 = 250 remaining runs.
Run rate = 250/40 = 6.25.
3.2 = sum of runs/10
Sum = 3.2×10 = 32
40 over total runs 282.
So, 282 - 32 = 250 remaining runs.
Run rate = 250/40 = 6.25.
(43)
Srijan said:
9 months ago
I understand the solution with the help of the given explanation. Thanks, everyone.
(24)
Arunpandiyan said:
2 months ago
In the first 10 overs, we got a total runs is 10 * 3.2 = 32
And after 40 runs they give a total of runs 282.
So, we find the remaining 282-32/40 = 6.25 is the answer.
And after 40 runs they give a total of runs 282.
So, we find the remaining 282-32/40 = 6.25 is the answer.
(11)
Bhavik said:
2 weeks ago
10 overs -> 3.2 RR ==> so we get 32runs in 10overs.
40 overs -> target = 282 - 32 = 250 so RR ==> 250/40 = 6.25.
40 overs -> target = 282 - 32 = 250 so RR ==> 250/40 = 6.25.
(3)
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