Aptitude - Average - Discussion

First 10 - run rate 3.2
3.2 = sum of runs/10
Sum = 3.2×10 = 32
40 over total runs 282.
So, 282 - 32 = 250 remaining runs.
Run rate = 250/40 = 6.25.

I understand the solution with the help of the given explanation. Thanks, everyone.

In the first 10 overs, we got a total runs is 10 * 3.2 = 32
And after 40 runs they give a total of runs 282.
So, we find the remaining 282-32/40 = 6.25 is the answer.

10 overs -> 3.2 RR ==> so we get 32runs in 10overs.
40 overs -> target = 282 - 32 = 250 so RR ==> 250/40 = 6.25.

@All.
For simple understanding.

Total Runs at the end = 282 Runs
Run Rate of 1st 10 overs = 3.2
Total Runs score in 1st 10 overs = 10*3.2 = 32Runs.

The question is what should be the Run Rate of the next 40 overs to get 282 Runs at the end of innings?
Let the Run Rate of 40overs be x
Total runs scored in 40 overs = 40*x = 40x.
We know that Total runs= Runs in 1st 10overs+runs in next 40 overs
i.e : 282 = 32 + 40x.
282-32= 40x,
250 = 40x,
x = 250/40,
x = 6.25.

Hence And 6.25 Run Rate is the right answer.

For cross-checking

282 = 32 + (40*6.25),
282 = 32 + 250,
282 = 282.