Aptitude - Average - Discussion

What is the actual formula for this type of questions?

In the first 10 overs the run rate was = 3.2.

Than total run is = 32.

Where total target is - 282.

Let the remaining 40 overs run rate is = x.

32+40x = 282.

40x = 250.

x = 25/4 = 6.25 answer.

Using basics of cricket.

Runs in 10 overs at the rate of 3.2 = 32.

Target 282.

Remaining runs 282-32 = 250.

Remaining overs 40.

Thus run rate 250/40 = 6.25.

Formula used for this type of questions?

What is the formula for this sum?

@Gautam - Sorry to say but your solution is wrong.
@Aymen - The solution for your problem stated.

"The average of three numbers is 8, that of the first two is 11. Find the third number?please help me." is:

Let three numbers be x,y,z.
Average of first three numbers is 8.
Hence, x+y+z/3 = 8.
=> x+y+z = 24.....eq(1).

Average of first two numbers is = 11.
Hence, x+y/2 = 11.
=> x+y = 22....eq(2).

Now substitute eq(2) value in eq(1).
Thus, 22+z = 24.
=> z = 24-22 = 2.
Answer is z = 2.
:).

The total target for 50 overs is 282 out of that first 10 overs they scored at The run rate of 3.2, which means they scored 32,
For remaining 40 overs the target is 282-32=250,

For 40 overs the target is 250.

Then for 1 over it is 250/40 = 6.25.

@Aayush - Sorry to say but your solution is wrong.
@Aymen - The solution for your problem stated.

THE AVERAGE OF THREE NO.IS
X+Y+Z/3=8.

THE SUM OF FIRST TWO NO. IS 11,SO
(X+Y)+Z/3=8.
11+Z/3=8.

BY TRANSPOSITION,
11+Z=3*8.
11+Z=24.
Z=24-11.
Z=13.

i.e) X+Y=11.
Z=13.

HENCE THE AVG X+Y+Z/3=8.

SO, Gautam IS RIGHT YOU'RE WRONG Ayush.

Why we Divided 40 over because remaining over 30 and you also given the 10 over run ate?

Sorry @Palani your point of view to check answer is wrong!

GAUTAM AND AYUSH you BOTH are RIGHT.

Gautam takes the sum of first two number is 11, and Ayush takes the average first two number is 11.

So both answer is correct.