Online Aptitude Test  Aptitude Test 7
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 Total number of questions: 20.
 Time allotted: 30 minutes.
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Marks : 2/20
Test Review : View answers and explanation for this test.
L.C.M. of 5, 6, 7, 8 = 840.
Required number is of the form 840k + 3
Least value of k for which (840k + 3) is divisible by 9 is k = 2.
Required number = (840 x 2 + 3) = 1683.
617.00 6.017 0.617 + 6.0017  629.6357 
If  144  =  14.4  , then the value of x is: 
0.144  x 
144  =  14.4 
0.144  x 
144 x 1000  =  14.4  
144  x 
x =  14.4  = 0.0144 
1000 
3   1  2  simplifies to:  
3 
3   1  2  = (3)^{2} +  1  2   2 x 3 x  1  
3  3  3 
= 3 +  1   2 
3 
= 1 +  1 
3 
=  4 
3 
Let the average age of the whole team by x years.
11x  (26 + 29) = 9(x 1)
11x  9x = 46
2x = 46
x = 23.
So, average age of the team is 23 years.
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x  8) + (7x  8) + (9x  8) = 56
20x = 80
x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
 Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
 Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
 Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
 Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
 Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
Divya is twice as old as Shruti. What is the difference in their ages?  
I.  Five years hence, the ratio of their ages would be 9 : 5. 
II.  Ten years back, the ratio of their ages was 3 : 1. 
Let Divya's present age be D years and Shruti's present age b S years
Then, D = 2 x S D  2S = 0 ....(i)
I.  D + 5  =  9  ....(ii) 
S + 5  5 
II.  D  10  =  3  ....(iii) 
S  10  1 
From (ii), we get : 5D + 25 = 9S + 45 5D  9S = 20 ....(iv)
From (iii), we get : D  10 = 3S  30 D  3S = 20 ....(v)
Thus, from (i) and (ii), we get the answer.
Also, from (i) and (iii), we get the answer.
I alone as well as II alone give the answer. Hence, the correct answer is (C).
(256)^{0.16} x (256)^{0.09} = (256)^{(0.16 + 0.09)}
= (256)^{0.25}
= (256)^{(25/100)}
= (256)^{(1/4)}
= (4^{4})^{(1/4)}
= 4^{4(1/4)}
= 4^{1}
= 4
Let B's capital be Rs. x.
Then,  3500 x 12  =  2  
7x  3 
14x = 126000
x = 9000.
Let their investments be Rs. x for 14 months, Rs. y for 8 months and Rs. z for 7 months respectively.
Then, 14x : 8y : 7z = 5 : 7 : 8.
Now,  14x  =  5  98x = 40y y =  49  x 
8y  7  20 
And,  14x  =  5  112x = 35z z =  112  x =  16  x. 
7z  8  35  5 
x : y : z = x :  49  x  :  16  x  = 20 : 49 : 64. 
20  5 
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
 Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
 Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
 Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
 Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
 Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
Ravi, Gagan and Nitin are running a business firm in partnership. What is Gagan's share in the profit earned by them?  
I.  Ravi, Gagan and Nitin invested the amounts in the ratio of 2 : 4 : 7. 
II.  Nitin's share in the profit is Rs. 8750. 
Let us name Ravi, Gagan and Nitin by R, G and N respectively.
I. R : G : N = 2 : 4 : 7.
II. N = 8750..
From I and II, we get:
When N = 7, then G = 4.
When N = 8750, then G =  4  x 8750  = 5000.  
7 
Thus, both I and II are needed to get the answer.
Correct answer is (E).
Let the required number of revolutions made by larger wheel be x.
Then, More cogs, Less revolutions (Indirect Proportion)
14 : 6 :: 21 : x 14 x x = 6 x 21
x =  6 x 21 
14 
x = 9.
1 woman's 1 day's work =  1 
70 
1 child's 1 day's work =  1 
140 
(5 women + 10 children)'s day's work =  5  +  10  =  1  +  1  =  1  
70  140  14  14  7 
5 women and 10 children will complete the work in 7 days.
Work done by the waste pipe in 1 minute =  1    1  +  1  
15  20  24 
=  1    11  
15  120 
=   1  . [ve sign means emptying] 
40 
Volume of  1  part = 3 gallons. 
40 
Volume of whole = (3 x 40) gallons = 120 gallons.
Speed =  240  m/sec = 10 m/sec.  
24 
Required time =  240 + 650  sec = 89 sec.  
10 
Speed of train relative to jogger = (45  9) km/hr = 36 km/hr.
=  36 x  5  m/sec  
18 
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
Time taken =  360  sec  = 36 sec.  
10 
Relative speed =  = (45 + 30) km/hr  



We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
Required time =  500 x  6  = 24 sec.  
125 
Rate downstream =  1  x 60  km/hr = 6 km/hr.  
10 
Rate upstream = 2 km/hr.
Speed in still water =  1  (6 + 2) km/hr = 4 km/hr. 
2 
Required time =  5  hrs = 1  1  hrs = 1 hr 15 min.  
4  4 
Let the quantity of the wine in the cask originally be x litres.
Then, quantity of wine left in cask after 4 operations =  x  1   8  4  litres.  
x 
x(1  (8/x))^{4}  =  16  
x  81 
1   8  4  =  2  4  
x  3 
x  8  =  2  
x  3 
3x  24 = 2x
x = 24.
Total number of balls = (2 + 3 + 2) = 7.
Let S be the sample space.
Then, n(S)  = Number of ways of drawing 2 balls out of 7  
= ^{7}C_{2} `  


= 21. 
Let E = Event of drawing 2 balls, none of which is blue.
n(E)  = Number of ways of drawing 2 balls out of (2 + 3) balls.  
= ^{5}C_{2}  


= 10. 
P(E) =  n(E)  =  10  . 
n(S)  21 