Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 10)
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
3.6 sec
18 sec
36 sec
72 sec
Answer: Option

Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.

   = 36 x 5 m/sec

   = 10 m/sec.

Distance to be covered = (240 + 120) m = 360 m.

Time taken = 360 sec = 36 sec.
106 comments Page 1 of 11.

Chetana prajapati said:   3 months ago
Thankyou for explaining the answer.

Srideepa c said:   7 months ago
In this question, we have been asked to find the time taken by the train to pass the jogger when it is given that the jogger’s speed is 9 kmph and the train’s speed is 45 kmph and the jogger is 240 m ahead of a 120 m long train. To solve this question, we should know about relative speed, which is the speed of one object with respect to the other and when both objects are moving in the same direction, then their difference is taken as their relative speed. So, we can say that the relative speed of the train with respect to the jogger is, the speed of the train - speed of the jogger.

So, we get,

Relative speed of train = (45 - 9)kmph = 36 kmph.

So, if we consider the relative speed of the train as the original speed, then we have to assume that the jogger is standing. So, we can say that the train must travel a distance of (240 + 120) m = 360 m as the front of the engine and the jogger are 240 m apart and the engine is 120 m long.

Now, we know that 1 km = 1000 m and 1 hr = 3600 sec. So, we can say that, 36 kmph = 36×10003600=10.


We know that speed, distance, and time are related as, speed=distancetime.
It can also be written as, time=distancespeed.
Now, we know that the train has to travel 360 m with a speed of 10 mpsec. So, we can say that,
Time taken = 36010⇒36sec.
Hence, we can say that a 120 m long train with a speed of 45 kmph at a distance of 240 m from a jogger who is running at a speed of 9 kmph will cross the jogger in 36 sec.
Therefore, the correct option is option C.

Profie said:   8 months ago
The total distance covered by the train will be 288m with its original speed. Thereafter relative velocity will take place. So, the actual answer is 35.04 sec

Jom said:   9 months ago
Why we consider the length of the track?

Sanketh said:   11 months ago

Ahead means behind that's why we should minus the speed because they are in the same direction.

Bahu said:   1 year ago
Because if two trains run in the same direction the Speed of train will decrease to pass another train.

Shri.. said:   2 years ago

Because we have to calculate the relative speed of both objects.

Train speed = 45 kmph.
Jogger speed= 9 kmph.

Swetty said:   2 years ago
Why 45-9? Explain Please.

Sourav said:   2 years ago
I also agree with you @Ravi by the time when the train takes 36 sec to cross the jogger. The jogger also traveled some dist at that 36 sec of time. Jogger speed is 9km/hr which is 2. 5m/sec which means joggers must have covered 2. 5x36=90 m of dist that's mean now the train has to cover 90 m more to actually cross that jogger.

Am I correct? Please anyone explain me.

Ravi said:   3 years ago
Even the jogger is running at a particular speed and is not idle so why are we not considering the distance travelled by the jogger when the train passes him?

Please anyone clarify this.

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