Aptitude - Problems on Trains
Exercise : Problems on Trains - General Questions
- Problems on Trains - Formulas
- Problems on Trains - General Questions
- Problems on Trains - Data Sufficiency 1
- Problems on Trains - Data Sufficiency 2
- Problems on Trains - Data Sufficiency 3
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
Speed = | ![]() |
240 | ![]() |
24 |
![]() |
![]() |
240 + 650 | ![]() |
10 |
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
= | ![]() |
10 x | 5 | ![]() |
18 |
= | ![]() |
25 | ![]() |
9 |
![]() |
2x | = | 25 |
36 | 9 |
2x = 100
x = 50.
8.
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Answer: Option
Explanation:
Formula for converting from km/hr to m/s: X km/hr = | ![]() |
X x | 5 | ![]() |
m/s. |
18 |
Therefore, Speed = | ![]() |
45 x | 5 | ![]() |
= | 25 | m/sec. |
18 | 2 |
Total distance to be covered = (360 + 140) m = 500 m.
Formula for finding Time = | ![]() |
Distance | ![]() |
Speed |
![]() |
![]() |
500 x 2 | ![]() |
= 40 sec. |
25 |
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
= | ![]() |
150 x | 5 | ![]() |
18 |
= | ![]() |
125 | ![]() |
3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = | ![]() |
2000 x | 3 | ![]() |
125 |
10.
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: Option
Explanation:
Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
= | ![]() |
36 x | 5 | ![]() |
18 |
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
![]() |
![]() |
360 | ![]() |
= 36 sec. |
10 |
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