Aptitude - Problems on Trains
Exercise : Problems on Trains - General Questions
- Problems on Trains - Formulas
- Problems on Trains - General Questions
- Problems on Trains - Data Sufficiency 1
- Problems on Trains - Data Sufficiency 2
- Problems on Trains - Data Sufficiency 3
11.
A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
Answer: Option
Explanation:
Relative speed = (120 + 80) km/hr
= | ![]() |
200 x | 5 | ![]() |
18 |
= | ![]() |
500 | ![]() |
9 |
Let the length of the other train be x metres.
Then, | x + 270 | = | 500 |
9 | 9 |
x + 270 = 500
x = 230.
12.
A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?
Answer: Option
Explanation:
Speed = | ![]() |
72 x | 5 | ![]() |
= 20 m/sec. |
18 |
Time = 26 sec.
Let the length of the train be x metres.
Then, | x + 250 | = 20 |
26 |
x + 250 = 520
x = 270.
13.
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
Answer: Option
Explanation:
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
![]() |
(100 + 100) | = 3x |
8 |
24x = 200
![]() |
25 | . |
3 |
So, speed of the faster train = | 50 | m/sec |
3 |
= | ![]() |
50 | x | 18 | ![]() |
3 | 5 |
= 60 km/hr.
14.
Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
Answer: Option
Explanation:
Relative speed = (60 + 40) km/hr = | ![]() |
100 x | 5 | ![]() |
= | ![]() |
250 | ![]() |
18 | 9 |
Distance covered in crossing each other = (140 + 160) m = 300 m.
Required time = | ![]() |
300 x | 9 | ![]() |
= | 54 | sec = 10.8 sec. |
250 | 5 |
15.
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Answer: Option
Explanation:
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.
= | ![]() |
66 x | 5 | ![]() |
18 |
= | ![]() |
55 | ![]() |
3 |
![]() |
![]() |
110 x | 3 | ![]() |
55 |
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