Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 15)
15.
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Answer: Option
Explanation:
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.
| = |  |
66 x | 5 |  m/sec |
| 18 |
| = | |
55 | m/sec. |
| 3 |
 Time taken to pass the man = |
|
110 x | 3 | sec = 6 sec. |
| 55 |
Discussion:
35 comments Page 1 of 4.
Smith Patel said:
5 years ago
@Melvin Michael.
It's true that if we consider the distance taken by a man in running towards the train , the answer becomes 6.6.
But the man is running in the opposite direction so sign of that distance becomes negative and hence,
Ans becomes 5.5.
It's true that if we consider the distance taken by a man in running towards the train , the answer becomes 6.6.
But the man is running in the opposite direction so sign of that distance becomes negative and hence,
Ans becomes 5.5.
(3)
Sunil said:
6 years ago
Hi, I don't know how it is calculated.
(66*5/18) = 55/3.
(66*5/18) = 55/3.
(2)
Melvin Michael said:
6 years ago
Hi, I am confused with the solution provided here:
Let the time taken be - X.
Relative speed = 66 KMPH = 55/3 meters/sec.
Distance = 110 + (5/3)X, (5/3)X being the distance covered by man.
Distance = Speed * Time.
(5/3)X +110 = (55/3) * X.
On resolving this, X comes to 6.6 seconds.
Please correct me when I am wrong.
Let the time taken be - X.
Relative speed = 66 KMPH = 55/3 meters/sec.
Distance = 110 + (5/3)X, (5/3)X being the distance covered by man.
Distance = Speed * Time.
(5/3)X +110 = (55/3) * X.
On resolving this, X comes to 6.6 seconds.
Please correct me when I am wrong.
(2)
Vishnu said:
6 years ago
@All.
The man is running right so so we need to find the distance travelled by him then only we can add with a distance of the train.
The man is running right so so we need to find the distance travelled by him then only we can add with a distance of the train.
(1)
Vamshi said:
7 years ago
@Arun.
110/x = 55/3.
X = 110 * 3/55.
110/x = 55/3.
X = 110 * 3/55.
(1)
Sarang said:
7 years ago
Distance =speed *time.
110m=60+6km/h*time,
110=66*5/18*time,
110=66*.27*time,
110=17.8 or 18 *time,
Time=110/18=6 s.
110m=60+6km/h*time,
110=66*5/18*time,
110=66*.27*time,
110=17.8 or 18 *time,
Time=110/18=6 s.
(5)
Pritam said:
8 years ago
Guys, we have to subtract the distance of the man i.e distance from 110.
(1)
Chetan said:
8 years ago
Why add 60km/hr+6km/hr there is not mention in question like both object move in parallel if they move in parallel, we can say add 60+6 but why here is use like this?
Tanveer said:
8 years ago
Relative speed, We have to add the speed in opposite direction and have to subtract in the same direction am I right? Please help.
(1)
Samir said:
9 years ago
66 * 5/18,
So
66/6 =11,
18/6 = 3,
11* 5 = 55.
Hence 55/3.
So
66/6 =11,
18/6 = 3,
11* 5 = 55.
Hence 55/3.
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