Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 15)
15.
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
5 sec
6 sec
7 sec
10 sec
Answer: Option
Explanation:

Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.

   = 66 x 5 m/sec
18

   = 55 m/sec.
3

Time taken to pass the man = 110 x 3 sec = 6 sec.
55

Discussion:
35 comments Page 1 of 4.

RPrabha said:   2 decades ago
Additive speeds are only valid for the objects moving in th esame direction. Here only difference is applcable. so the answer would be 7 sec approx.
(1)

Ramesh karthick said:   2 decades ago
@Praba.

Your answer is wrong. How will you said diff is applicable. Because speed opposite direction. So additive is applicable.
(1)

Tarun said:   2 decades ago
Hey ramesh,

If you know the derivation please let us know.
(1)

Priyavel said:   1 decade ago
hi friend
tarun
step 1) opposite direction so we add it(60+6)
step 2) we convert km/hour into m/sec so we multiply by 5/18
step 3)speed=distance/time
spep 4) time=distance/speed

i think now u get it clearly.

Chellem said:   1 decade ago
How it comes 5/18? anyone please reply.

Shanmu said:   1 decade ago
1 km=1000m
1 hour=3600 seconds

to convert from km/hour into m/sec
1000/3600=5/18 m/sec

got it !

Arun said:   1 decade ago
hi.. can anyone just tell me why we r 55/3 as reciprocal to 3/55........? reply if u know....

Mini said:   1 decade ago
@Arun

speed=distance/time

time=distance/speed

speed = 66*5/18 [Converting km/hr to m/sec]

= 55/3 m/sec.


Therefore, time = 110/55*3

= 110*3/55

= 6 sec

i think u will understand now

Sarah said:   1 decade ago
@mini:

Nice explanation friend.

Shivani said:   1 decade ago
Here is solution in simple way:.
As we know speed will add in case of opp direction so,
Speed= (60+6) =66km/h.
66*5/18=55/3m/sec (for change km/h into m/sec).
Length=110m.
Distance=s*t.
110=55/3*t.
Hence.
t=330/55=6sec.


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