Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 15)
15.
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Answer: Option
Explanation:
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.
= | ![]() |
66 x | 5 | ![]() |
18 |
= | ![]() |
55 | ![]() |
3 |
![]() |
![]() |
110 x | 3 | ![]() |
55 |
Discussion:
35 comments Page 2 of 4.
Thili said:
1 decade ago
To pass the man train should go distance of train and the which was ran by the man.
Then why don't you care about the distance of man run. Train should go that distance also to pass the train.
Then why don't you care about the distance of man run. Train should go that distance also to pass the train.
Shashi said:
1 decade ago
Hai friends please can you provide some formulas which are related to these problems.
Raju said:
1 decade ago
@Thili.
I agree with you.
The distance the man runs (X) towards train will be decrease the total distance, i.e 110-X mts.
Hence the time will decrease below 6 seconds.
Also since we have 2 variables distance traveled b the man towards train and the time taken for train to pass the man.
Can someone explain this solution clearly.
I agree with you.
The distance the man runs (X) towards train will be decrease the total distance, i.e 110-X mts.
Hence the time will decrease below 6 seconds.
Also since we have 2 variables distance traveled b the man towards train and the time taken for train to pass the man.
Can someone explain this solution clearly.
Mona said:
1 decade ago
In the question they did not mentioned that the whether the train is moving on platform are not. If they mentioned any pole are platform means we want to consider the distance of man moving in opposite direction. So I think we don't consider the distance.
Buvana said:
1 decade ago
Please any one give the reason for not considering distance covered by man.
Buvana said:
1 decade ago
Please any one give the reason for not considering distance covered by man.
Anjali said:
1 decade ago
As of the direction the relative speed would be 60+6=66. Convert it to m/sec as required to the answer. You will get 55/3 mtr/sec.
So, 55/3 = 110/t. T = 6 sec and done.
So, 55/3 = 110/t. T = 6 sec and done.
Salman said:
10 years ago
Both the man and train moving in opposite to each other so while the train crosses man, man will also move some distance so total distance travel by train will be different not only its own length.
Hence the answer is 6.6 sec.
Hence the answer is 6.6 sec.
Rashmi said:
10 years ago
Case 1: When they are in opposite direction.
Length of train in m = (Speed of train + Speed of man) in m/sec*time in sec.
Case 2: When they are in same direction.
Length of train in m = (Speed of train - Speed of man) in m/sec*time in sec.
110 m = (60 kmph + 6 kmph) * time (sec).
110 m = 66 kmph * time (sec).
110 m = 66*5/18 (m/sec) * time (sec).
Time (sec) = 110/18.333.
Time (sec) = 6 sec.
Hint: To convert km/hr = m/sec multiply by 5/18.
To convert m/sec = km/hr multiply by 18/5.
Length of train in m = (Speed of train + Speed of man) in m/sec*time in sec.
Case 2: When they are in same direction.
Length of train in m = (Speed of train - Speed of man) in m/sec*time in sec.
110 m = (60 kmph + 6 kmph) * time (sec).
110 m = 66 kmph * time (sec).
110 m = 66*5/18 (m/sec) * time (sec).
Time (sec) = 110/18.333.
Time (sec) = 6 sec.
Hint: To convert km/hr = m/sec multiply by 5/18.
To convert m/sec = km/hr multiply by 18/5.
(1)
Sanidhya said:
9 years ago
Hi all.
Here we have considered the distance taken by train coming in opposite direction in almost all the problems. So here why we have not considered the distance taken by man.
Here we have considered the distance taken by train coming in opposite direction in almost all the problems. So here why we have not considered the distance taken by man.
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