Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 15)
15.
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
5 sec
6 sec
7 sec
10 sec
Answer: Option
Explanation:

Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.

   = 66 x 5 m/sec
18

   = 55 m/sec.
3

Time taken to pass the man = 110 x 3 sec = 6 sec.
55

Discussion:
35 comments Page 3 of 4.

Faizal said:   9 years ago
The speed can be added only if the two objects moving in opposite directions and if same direction then it should be subtracted.

Koyal said:   9 years ago
Moving in the same direction that's why 60 + 6 = 66
Speed = 66 * 5/18 = 55/3.
Time = 110/(55/3).
= 110 * 3/55.
= 6 sec.

Rahul raj said:   9 years ago
Because train are moving across the man.

The man is not considered as pole so only train distance is total distance.

Manish said:   9 years ago
Guys why don't you'll go through the formulas given at the beginning of all the topic as this will clear most of the questions asked here at the beginning itself.

Priya said:   9 years ago
Hi.

How is possible to come 55/3?

Please advice me.
(1)

Samir said:   9 years ago
66 * 5/18,
So
66/6 =11,
18/6 = 3,
11* 5 = 55.

Hence 55/3.

Tanveer said:   8 years ago
Relative speed, We have to add the speed in opposite direction and have to subtract in the same direction am I right? Please help.
(1)

Chetan said:   8 years ago
Why add 60km/hr+6km/hr there is not mention in question like both object move in parallel if they move in parallel, we can say add 60+6 but why here is use like this?

Pritam said:   8 years ago
Guys, we have to subtract the distance of the man i.e distance from 110.
(1)

Sarang said:   7 years ago
Distance =speed *time.
110m=60+6km/h*time,
110=66*5/18*time,
110=66*.27*time,
110=17.8 or 18 *time,
Time=110/18=6 s.
(5)


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