Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
Speed = | 240 | m/sec = 10 m/sec. | |
24 |
Required time = | 240 + 650 | sec = 89 sec. | |
10 |
Discussion:
200 comments Page 1 of 20.
Pachu said:
6 days ago
Given answer 89 is correct. I too agree.
Mnkumar said:
6 months ago
@All.
What I understand is the train starting point and cross-platform is 650 meters. The train exit point after crossing the platform is 240 meters so you should add 240 + 650.
What I understand is the train starting point and cross-platform is 650 meters. The train exit point after crossing the platform is 240 meters so you should add 240 + 650.
Piyush said:
8 months ago
To solve this, we need to consider the additional distance the train needs to cover to pass the platform.
First, let's find the speed of the train:
Speed = Distance/Time.
Speed = 240 m/24 s.
Speed = 10 m/s.
Now, the train needs to cover the length of the platform (650 m) plus its length (240 m) relative to the platform. So, the total distance to cover is 650 m + 240 m = 890 m.
Time = Distance/Speed.
Time = 890 m/10 m/s.
Time = 89 seconds.
So, it will take 89 seconds for the train to pass the platform.
First, let's find the speed of the train:
Speed = Distance/Time.
Speed = 240 m/24 s.
Speed = 10 m/s.
Now, the train needs to cover the length of the platform (650 m) plus its length (240 m) relative to the platform. So, the total distance to cover is 650 m + 240 m = 890 m.
Time = Distance/Speed.
Time = 890 m/10 m/s.
Time = 89 seconds.
So, it will take 89 seconds for the train to pass the platform.
(27)
SalahaKA said:
12 months ago
WHY NOT 65?
We got train speed =10.
Then we can directly find the time right?
i.e time = 65 because t=d/s=>650/10 = 65.
We got train speed =10.
Then we can directly find the time right?
i.e time = 65 because t=d/s=>650/10 = 65.
(52)
Aaa said:
1 year ago
I think the length of a platform is greater than the length of the trian so to pass the platform we should be adding each lengths.
(14)
Shah sonu said:
2 years ago
The length of the train = 240m.
time to cross the pole = 24sec.
Length of the station =650m.
so,
The speed of the train = length of the train /time to cross the pole * 18/5.
So,
= 240/24*18/5
= 10*18/5
= 180/5.
The speed of the train = 36km/h.
And the time to cross the station = 240+650/36*18/5.
= 890*18/36*5
= 16020/180.
Final answer = 89sec.
So, option B is the right answer.
time to cross the pole = 24sec.
Length of the station =650m.
so,
The speed of the train = length of the train /time to cross the pole * 18/5.
So,
= 240/24*18/5
= 10*18/5
= 180/5.
The speed of the train = 36km/h.
And the time to cross the station = 240+650/36*18/5.
= 890*18/36*5
= 16020/180.
Final answer = 89sec.
So, option B is the right answer.
(14)
Lava said:
2 years ago
To solve this problem, we need to first determine the speed of the train. We can use the formula:
Speed = Distance/Time.
From the given information, we know that the length of the train is 240 meters and it passes a pole in 24 seconds. Therefore, the speed of the train is:
Speed = 240/24.
Speed = 10 m/s.
Now, we need to find out how long it will take for the train to pass a platform that is 650 meters long. Let's assume that the front of the train just reaches the beginning of the platform at time t=0.
As the train passes over the entire length of the platform, it will cover a distance equal to the sum of the length of the train and the length of the platform.
Total distance to be covered = 240 + 650 = 890 meters
To find the time taken for the train to cover this distance, we can use the formula:
Time = Distance / Speed
Time = 890 / 10
Time = 89 seconds
Therefore, it will take the train 89 seconds to pass a platform that is 650 meters long.
Speed = Distance/Time.
From the given information, we know that the length of the train is 240 meters and it passes a pole in 24 seconds. Therefore, the speed of the train is:
Speed = 240/24.
Speed = 10 m/s.
Now, we need to find out how long it will take for the train to pass a platform that is 650 meters long. Let's assume that the front of the train just reaches the beginning of the platform at time t=0.
As the train passes over the entire length of the platform, it will cover a distance equal to the sum of the length of the train and the length of the platform.
Total distance to be covered = 240 + 650 = 890 meters
To find the time taken for the train to cover this distance, we can use the formula:
Time = Distance / Speed
Time = 890 / 10
Time = 89 seconds
Therefore, it will take the train 89 seconds to pass a platform that is 650 meters long.
(67)
Manu said:
2 years ago
Here is the solution
Just apply required time formula.
Required time = distance /speed.
In this case, train Len = 240 + platform = 650/speed.
And req tiime = 240 + 650/10 = 89 m/s thats it.
Just apply required time formula.
Required time = distance /speed.
In this case, train Len = 240 + platform = 650/speed.
And req tiime = 240 + 650/10 = 89 m/s thats it.
(12)
Mansi Bora said:
2 years ago
Why did we add 240 to 650?
Since we only want to find the time taken to cover 650m.
Anyone, please explain me.
Since we only want to find the time taken to cover 650m.
Anyone, please explain me.
(25)
PARAMESHWAR said:
3 years ago
I THINK ANS IS 65 SEC BECAUSE;
Directly calculate the answer;
240 = 24,
650 = X.
Cross multiplication.
240X = 15600.
X = 15600/240.
X = 65 Sec.
Directly calculate the answer;
240 = 24,
650 = X.
Cross multiplication.
240X = 15600.
X = 15600/240.
X = 65 Sec.
(45)
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