Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 10)
10.
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
3.6 sec
18 sec
36 sec
72 sec
Answer: Option
Explanation:

Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.

   = 36 x 5 m/sec
18

   = 10 m/sec.

Distance to be covered = (240 + 120) m = 360 m.

Time taken = 360 sec = 36 sec.
10
Discussion:
106 comments Page 2 of 11.

Dheeraj Shenoy said:   4 years ago
The jogger is running at 9kmph.

240m ahead from 120m long train.

When the train covers 240m at speed of 45kmph in t = 96/5 sec in the same time the jogger covers 48m.

Since he is jogging at a particular speed so the total distance covered by the train to pass the jogger would be 120+240+48.

Then, how it could be 240 +120?
(1)

Dheeraj Shenoy said:   4 years ago
The jogger is running at 9kmph.

240m ahead from 120m long train.

When the train covers 240m at speed of 45kmph in t = 96/5 sec in the same time the jogger covers 48m.

Since he is jogging at a particular speed so the total distance covered by the train to pass the jogger would be 120+240+48.

Then, how it could be 240 +120?

Kevin said:   4 years ago
The distance to be covered is the length from the train to the jogger (240) And we are adding 120 because we need to know the time when the whole train passes the jogger.

Chirag said:   4 years ago
Why we have taken the distance covered by train as (120m +240m)? why to add the length of the track? Please explain.

Syrus said:   5 years ago
When the train is moving towards the jogger the jogger is still running at 9Kmph or 2.5 m/sec so by the time the engine reaches 240mtrs the jogger would've moved forward.

Time taken for front of train to cover 240 mtrs = 24 secs (time = distance / speed{relative = 10 m/s})

Also the distance travelled by jogger in this 24 secs is = 2.5 mtr/sec * 24 sec = 60 mtrs
so in order for the train to completely pass the jogger, it has to travel 60 mtrs more.

Total distance = 60 + 120 = 180 m.
Speed = 10 m/s.
Time = 18 sec.

Total time = 18 + 24 = 42 sec.

Is this method is correct?

Madhav Kulkarni said:   6 years ago
Speed of jogger=9km/h=9*(5/18)=2.5m/s.
Length=240.

Length of train = 120m.
Speed of train = 45km/h=45(5/18)=12.15m/s.

Relative Length=240+120=360m.
Relative speed=12.15-2.5=9.65m/s.

Speed = Distance/Time.
9.65 = 360/Time.
Time = 360/9.65.
= 36.

Abhishek said:   6 years ago
The jogger is ahead of the train by 240m and the question asks us to find the time train takes to pass the jogger, should we consider the time taken to cover distance of 240m and then add time take to cross the jogger.

Sangay said:   6 years ago
How come 5/8? Please explain.
(1)

Arpan Manchanda said:   6 years ago
@All.

Please let me know why we have considered the complete length of the track, may be jogger is in half of the way or but the question here is train is crossing jogger, they are running in the same direction hence we have considered relative velocity but when the train is passing a jogger, jogger don't have any length. Please elaborate.

Rohan said:   6 years ago
Why is the total distance taken as 240+120?


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