# Aptitude - Square Root and Cube Root - Discussion

Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 13)

13.

3 - | 1 | 2 | simplifies to: | ||

3 |

Answer: Option

Explanation:

3 - | 1 | 2 | = (3)^{2} + |
1 | 2 | - 2 x 3 x | 1 | ||||

3 | 3 | 3 |

= 3 + | 1 | - 2 |

3 |

= 1 + | 1 |

3 |

= | 4 |

3 |

Discussion:

9 comments Page 1 of 1.
Aswin said:
5 years ago

In this sum, why don't we use BODMAS condition?

Yash Badgujar said:
7 years ago

= sqrt3/1 - 1/sqrt3.

= sqrt9 - 1/sqrt3.

= (3 - 1/sqrt3)^2.

We know that,

(a/b)^2 = a^2/b^2.

so,

= (2^2)/(sqrt3^2).

= 4/sqrt9.

= 4/3.

= sqrt9 - 1/sqrt3.

= (3 - 1/sqrt3)^2.

We know that,

(a/b)^2 = a^2/b^2.

so,

= (2^2)/(sqrt3^2).

= 4/sqrt9.

= 4/3.

Simi said:
7 years ago

Use the formula:

(a-b)^2 = a^2 + b^2 - 2(a*b).

(a-b)^2 = a^2 + b^2 - 2(a*b).

Joha said:
7 years ago

Any one please explain this sum?

Joslin said:
8 years ago

Taking LCM.

= (sqrt3- 1/sqrt3)^2.

= ( (3-1)/sqrt3)^2.

= (2/sqrt3)^2.

= 4/3.

= (sqrt3- 1/sqrt3)^2.

= ( (3-1)/sqrt3)^2.

= (2/sqrt3)^2.

= 4/3.

Amit said:
8 years ago

It is (a-b)square = (a square+b square-2ab).

Kalaiarasi said:
8 years ago

How to calculate LCM?

Abhilash said:
9 years ago

By doing LCM b/w root3 and 1/root3 also we can get that easily.

Munna said:
1 decade ago

Good caluclation.

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