Aptitude - Square Root and Cube Root - Discussion
Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 13)
13.
 |
3 - | 1 |  |
2 | simplifies to: |
| 3 |
Answer: Option
Explanation:
|
3 - | 1 | |
2 | = (3)2 + | |
1 | |
2 | - 2 x 3 x | 1 |
| 3 | 3 | 3 |
| = 3 + | 1 | - 2 |
| 3 |
| = 1 + | 1 |
| 3 |
| = | 4 |
| 3 |
Discussion:
9 comments Page 1 of 1.
Aswin said:
5 years ago
In this sum, why don't we use BODMAS condition?
Yash Badgujar said:
7 years ago
= sqrt3/1 - 1/sqrt3.
= sqrt9 - 1/sqrt3.
= (3 - 1/sqrt3)^2.
We know that,
(a/b)^2 = a^2/b^2.
so,
= (2^2)/(sqrt3^2).
= 4/sqrt9.
= 4/3.
= sqrt9 - 1/sqrt3.
= (3 - 1/sqrt3)^2.
We know that,
(a/b)^2 = a^2/b^2.
so,
= (2^2)/(sqrt3^2).
= 4/sqrt9.
= 4/3.
Simi said:
7 years ago
Use the formula:
(a-b)^2 = a^2 + b^2 - 2(a*b).
(a-b)^2 = a^2 + b^2 - 2(a*b).
Joha said:
7 years ago
Any one please explain this sum?
Joslin said:
8 years ago
Taking LCM.
= (sqrt3- 1/sqrt3)^2.
= ( (3-1)/sqrt3)^2.
= (2/sqrt3)^2.
= 4/3.
= (sqrt3- 1/sqrt3)^2.
= ( (3-1)/sqrt3)^2.
= (2/sqrt3)^2.
= 4/3.
Amit said:
8 years ago
It is (a-b)square = (a square+b square-2ab).
Kalaiarasi said:
8 years ago
How to calculate LCM?
Abhilash said:
9 years ago
By doing LCM b/w root3 and 1/root3 also we can get that easily.
Munna said:
1 decade ago
Good caluclation.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers