# Aptitude - Pipes and Cistern

## Why Aptitude Pipes and Cistern?

In this section you can learn and practice Aptitude Questions based on "Pipes and Cistern" and improve your skills in order to face the interview, competitive examination and various entrance test (CAT, GATE, GRE, MAT, Bank Exam, Railway Exam etc.) with full confidence.

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## Where can I get Aptitude Pipes and Cistern Interview Questions and Answers (objective type, multiple choice)?

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## How to solve Aptitude Pipes and Cistern problems?

You can easily solve all kind of Aptitude questions based on Pipes and Cistern by practicing the objective type exercises given below, also get shortcut methods to solve Aptitude Pipes and Cistern problems.

### Exercise :: Pipes and Cistern - General Questions

1.

Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?

A.
 5 11
B.
 6 11
C.
 7 11
D.
 8 11

Explanation:

 Part filled by (A + B + C) in 3 minutes = 3 1 + 1 + 1 = 3 x 11 = 11 . 30 20 10 60 20

 Part filled by C in 3 minutes = 3 . 10 Required ratio = 3 x 20 = 6 . 10 11 11

2.

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:

A.
 1 13 hours 17
B.
 2 8 hours 11
C.
 3 9 hours 17
D.
 4 1 hours 2

Explanation:

 Net part filled in 1 hour 1 + 1 - 1 = 17 . 5 6 12 60 The tank will be full in 60 hours i.e., 3 9 hours. 17 17

3.

A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 hours to fill the tank. The leak can drain all the water of the tank in:

A.
 4 1 hours 3
B. 7 hours
C. 8 hours
D. 14 hours

Explanation:

 Work done by the leak in 1 hour = 1 - 3 = 1 . 2 7 14 Leak will empty the tank in 14 hrs.

4.

Two pipes A and B can fill a cistern in 37 minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the B is turned off after:

 A. 5 min. B. 9 min. C. 10 min. D. 15 min.

Explanation:

Let B be turned off after x minutes. Then,

Part filled by (A + B) in x min. + Part filled by A in (30 -x) min. = 1. x 2 + 1 + (30 - x). 2 = 1 75 45 75 11x + (60 -2x) = 1 225 75 11x + 180 - 6x = 225. x = 9.

5.

A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is:

 A. 6 hours B. 10 hours C. 15 hours D. 30 hours

Explanation:

Suppose, first pipe alone takes x hours to fill the tank .

Then, second and third pipes will take (x -5) and (x - 9) hours respectively to fill the tank. 1 + 1 = 1 x (x - 5) (x - 9) x - 5 + x = 1 x(x - 5) (x - 9) (2x - 5)(x - 9) = x(x - 5) x2 - 18x + 45 = 0

(x - 15)(x - 3) = 0 x = 15.    [neglecting x = 3]