Aptitude - Pipes and Cistern
Exercise : Pipes and Cistern - General Questions
- Pipes and Cistern - Formulas
- Pipes and Cistern - General Questions
- Pipes and Cistern - Data Sufficiency 1
- Pipes and Cistern - Data Sufficiency 2
11.
One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:
Answer: Option
Explanation:
Let the slower pipe alone fill the tank in x minutes.
Then, faster pipe will fill it in | x | minutes. |
3 |
1 | + | 3 | = | 1 | |
x | x | 36 |
4 | = | 1 | |
x | 36 |
x = 144 min.
12.
A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?
Answer: Option
Explanation:
Part filled by (A + B) in 1 minute = | 1 | + | 1 | = | 1 | . | ||
60 | 40 | 24 |
Suppose the tank is filled in x minutes.
Then, | x | 1 | + | 1 | = 1 | ||
2 | 24 | 40 |
x | x | 1 | = 1 | |
2 | 15 |
x = 30 min.
13.
A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
Answer: Option
Explanation:
Time taken by one tap to fill half of the tank = 3 hrs.
Part filled by the four taps in 1 hour = | 4 x | 1 | = | 2 | . | ||
6 | 3 |
Remaining part = | 1 - | 1 | = | 1 | . | ||
2 | 2 |
2 | : | 1 | :: 1 : x | |
3 | 2 |
x = | 1 | x 1 x | 3 | = | 3 | hours i.e., 45 mins. | ||
2 | 2 | 4 |
So, total time taken = 3 hrs. 45 mins.
14.
Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:
Answer: Option
Explanation:
(A + B)'s 1 hour's work = | 1 | + | 1 | = | 9 | = | 3 | . | ||
12 | 15 | 60 | 20 |
(A + C)'s hour's work = | 1 | + | 1 | = | 8 | = | 2 | . | ||
12 | 20 | 60 | 15 |
Part filled in 2 hrs = | 3 | + | 2 | = | 17 | . | ||
20 | 15 | 60 |
Part filled in 6 hrs = | 3 x | 17 | = | 17 | . | ||
60 | 20 |
Remaining part = | 1 - | 17 | = | 3 | . | ||
20 | 20 |
Now, it is the turn of A and B and | 3 | part is filled by A and B in 1 hour. |
20 |
Total time taken to fill the tank = (6 + 1) hrs = 7 hrs.
15.
Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:
Answer: Option
Explanation:
Part filled in 2 hours = | 2 | = | 1 |
6 | 3 |
Remaining part = | 1 - | 1 | = | 2 | . | ||
3 | 3 |
(A + B)'s 7 hour's work = | 2 |
3 |
(A + B)'s 1 hour's work = | 2 |
21 |
C's 1 hour's work = { (A + B + C)'s 1 hour's work } - { (A + B)'s 1 hour's work }
= | 1 | - | 2 | = | 1 | ||
6 | 21 | 14 |
C alone can fill the tank in 14 hours.
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