Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 3)
3.
A pump can fill a tank with water in 2 hours. Because of a leak, it took 2
hours to fill the tank. The leak can drain all the water of the tank in:
hours to fill the tank. The leak can drain all the water of the tank in:Answer: Option
Explanation:
| Work done by the leak in 1 hour = |  |
1 | - | 3 |  |
= | 1 | . |
| 2 | 7 | 14 |
Leak will empty the tank in 14 hrs.
Discussion:
89 comments Page 1 of 9.
Sujitha said:
4 months ago
@Vivek Anand.
Your way of explanation is good but you have to take LCM for both numbers which is 1/2 - 3/7 = 7-2/14 = 5/14.
But you have taken 1/2-3/7 = 6-7 /14 =>this LCM is wrong.
Your way of explanation is good but you have to take LCM for both numbers which is 1/2 - 3/7 = 7-2/14 = 5/14.
But you have taken 1/2-3/7 = 6-7 /14 =>this LCM is wrong.
(2)
MAARA said:
4 months ago
If A=2 I mean 2 hours.
And, it takes 2 hours and 20 minutes to fill the tank so per 1 hour there is a drain of 10 minutes for two hours there is a drain of 20 minutes.
So, a * b/a-b = 2 * 7/3/2 - 7/3.
So 14/3/-1/3.
And by inverse 14 is the correct answer.
And, it takes 2 hours and 20 minutes to fill the tank so per 1 hour there is a drain of 10 minutes for two hours there is a drain of 20 minutes.
So, a * b/a-b = 2 * 7/3/2 - 7/3.
So 14/3/-1/3.
And by inverse 14 is the correct answer.
(1)
Gakir said:
5 months ago
A × B/ A - B.
2 × 7/3 ÷ 2 - 7/3,
14/3 ÷ 1/3.
14/3 × 13/1.
42/3 = 14ans.
2 × 7/3 ÷ 2 - 7/3,
14/3 ÷ 1/3.
14/3 × 13/1.
42/3 = 14ans.
(2)
Rajeev said:
5 months ago
We know that total time required to fill up a tank is xy/y-x(which includes the inlet and outlet).
Here this time is given by 7/3.
The value of y is 2. By solving this, we get x=14/13.
Correct me, If I am wrong.
Here this time is given by 7/3.
The value of y is 2. By solving this, we get x=14/13.
Correct me, If I am wrong.
(1)
DILIP KUMAR B K said:
3 years ago
As we know that rate (r)=work(w)/time(t).
Here the main thing is the work will remain constant.
Therefore,
As we have to find the time taken to empty the tank that is (T) with the leak will be;
W/T = (W/2 - W/(7/3)).
Cancelling "w" on both sides.
1/T = (1/2 - 3/7) = 1/14.
To get T,
We reciprocate the above result which is T = 14 hrs.
Here the main thing is the work will remain constant.
Therefore,
As we have to find the time taken to empty the tank that is (T) with the leak will be;
W/T = (W/2 - W/(7/3)).
Cancelling "w" on both sides.
1/T = (1/2 - 3/7) = 1/14.
To get T,
We reciprocate the above result which is T = 14 hrs.
(10)
KALAISELVAN E said:
3 years ago
@Jad.
Thanks for explaining.
Thanks for explaining.
(1)
Vivek anand said:
4 years ago
Guys, it's simple.
First thing;
A pump can fill water in 2 hours.
Due to the leak, it takes 2 1/3 hours.
They are asking in how many hours it can empty the tank through leak only.
So,
1. Tap ---> 2 hours.
2. Tap+leak ---> 2 1/3 hours (i.e) 7/3 hours.
3. Leak ---> ?
Leak = ( tap + leak ) - tap
= 1/7/3 - 1/2.
= 3/7 - 1/2,
= 6-7/14,
= -1/14.
Total leak = -14 - indicates leak or outlet etc.
First thing;
A pump can fill water in 2 hours.
Due to the leak, it takes 2 1/3 hours.
They are asking in how many hours it can empty the tank through leak only.
So,
1. Tap ---> 2 hours.
2. Tap+leak ---> 2 1/3 hours (i.e) 7/3 hours.
3. Leak ---> ?
Leak = ( tap + leak ) - tap
= 1/7/3 - 1/2.
= 3/7 - 1/2,
= 6-7/14,
= -1/14.
Total leak = -14 - indicates leak or outlet etc.
(60)
Appu said:
4 years ago
Shortcut;
x = 2.
y = 7/3 =====>(2 * 3) + 1.
x*y/y-x =====>14.
x = 2.
y = 7/3 =====>(2 * 3) + 1.
x*y/y-x =====>14.
(3)
Messi said:
4 years ago
Thanks for explaining @Suresh.
Suresh said:
4 years ago
Convert Hours into minutes.
A can fill in 2hrs i.e 120mins.
Leakage i.e a-b 2 1/3 is equal to 140mins.
Then capacity (LCM) is 840.
Efficiency : A is 7 and a-b is 6 and the difference is 1.
It can empty one part per minute out of 840 minutes. Then 840 parts can be emptied in 840 minutes.
Now convert 840 minutes to hours.
840/60 is 14 hours.
A can fill in 2hrs i.e 120mins.
Leakage i.e a-b 2 1/3 is equal to 140mins.
Then capacity (LCM) is 840.
Efficiency : A is 7 and a-b is 6 and the difference is 1.
It can empty one part per minute out of 840 minutes. Then 840 parts can be emptied in 840 minutes.
Now convert 840 minutes to hours.
840/60 is 14 hours.
(17)
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