Electronics and Communication Engineering - Exam Questions Papers

g = ac + bc

min c = 0, g = b and c = 1, g = a

So f = y + ya ⇒ y x + yg ...(i)

g = x b + x.a = x E + X.o ⇒ x E

from (i) f = y x + y x E.

The maximum phase lead is given by,

sin φ_m =

Where

Hence sin φ_m =

Hence φ_m = 30°.

(224)_r =

= (13)_r x (13)_r

∴ 2r² + 2r + 4 = (r + 3) (r + 3) = r² + 6r + 9

∴ r² - 4r - 5 = 0

∴ (r - 5) (r + 1) = 0

r = - 1 or r = 5

Negative base is not possible. Therefore base of the equation is 5.

Loss tangent

(i) for lossless dielectric, tan θ ≤ 1

(ii) for good conductor, tan θ >> 1

(iii) for lossy dielectric, tan θ = 1.

Reduced Diagram :

∴ R_AB = 3 || 6 = 2