Electronics and Communication Engineering - Exam Questions Papers - Discussion

12. 

For the given phase lead network, the maximum possible phase lead is

[A]. sin-1
[B]. 30°
[C]. 45°
[D]. 60°

Answer: Option B

Explanation:

The maximum phase lead is given by,

sin φm =

Where

Hence sin φm =

Hence φm = 30°.


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