Electronics and Communication Engineering - Exam Questions Papers - Discussion
Discussion Forum : Exam Questions Papers - Exam Paper 5 (Q.No. 13)
13.
Given (224)r = 
The value of the radix 'r' is :
The value of the radix 'r' is :Answer: Option
Explanation:
(224)r =
= (13)r x (13)r
∴ 2r2 + 2r + 4 = (r + 3) (r + 3) = r2 + 6r + 9
∴ r2 - 4r - 5 = 0
∴ (r - 5) (r + 1) = 0
r = - 1 or r = 5
Negative base is not possible. Therefore base of the equation is 5.
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