Exercise :: Digital Electronics - Section 1
- Digital Electronics - Section 1
- Digital Electronics - Section 2
- Digital Electronics - Section 3
- Digital Electronics - Section 4
- Digital Electronics - Section 5
- Digital Electronics - Section 6
- Digital Electronics - Section 7
- Digital Electronics - Section 8
- Digital Electronics - Section 9
- Digital Electronics - Section 10
- Digital Electronics - Section 11
- Digital Electronics - Section 12
- Digital Electronics - Section 13
- Digital Electronics - Section 14
- Digital Electronics - Section 15
- Digital Electronics - Section 16
- Digital Electronics - Section 17
- Digital Electronics - Section 18
- Digital Electronics - Section 19
- Digital Electronics - Section 20
- Digital Electronics - Section 21
- Digital Electronics - Section 22
- Digital Electronics - Section 23
- Digital Electronics - Section 24
| 36. | 7BF16 = __________ 2 |
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Answer: Option B Explanation: 7BF16 = 7 x 162 + 11 x 161 + 15 x 160 = 1983 in decimal = 0111 1011 1111 in binary. |
| 37. | For the minterm designation Y = ∑ m (1, 3, 5, 7) the complete expression is |
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Answer: Option B Explanation: Decimal number 1 = binary number 001 = A BC Decimal number 7 = binary number 111= ABC, Decimal number 3 = binary number 011= ABC Decimal number 5 = binary number 101= ABC . Hence result. |
| 38. | Zero suppression is not used in actual practice. |
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Answer: Option B Explanation: Zero suppression is commonly used. |
| 39. | A counter type A/D converter contains a 4 bit binary ladder and a counter driven by a 2 MHz clock. Then conversion time |
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Answer: Option A Explanation:
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| 40. | The hexadecimal number (3E8)16 is equal to decimal number |
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Answer: Option A Explanation: 3 x 162 + 14 x 161 + 8 = 1000. |