Exercise :: Digital Electronics - Section 3
- Digital Electronics - Section 1
- Digital Electronics - Section 2
- Digital Electronics - Section 3
- Digital Electronics - Section 4
- Digital Electronics - Section 5
- Digital Electronics - Section 6
- Digital Electronics - Section 7
- Digital Electronics - Section 8
- Digital Electronics - Section 9
- Digital Electronics - Section 10
- Digital Electronics - Section 11
- Digital Electronics - Section 12
- Digital Electronics - Section 13
- Digital Electronics - Section 14
- Digital Electronics - Section 15
- Digital Electronics - Section 16
- Digital Electronics - Section 17
- Digital Electronics - Section 18
- Digital Electronics - Section 19
- Digital Electronics - Section 20
- Digital Electronics - Section 21
- Digital Electronics - Section 22
- Digital Electronics - Section 23
- Digital Electronics - Section 24
1. | Octal number 12 is equal to decimal number |
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Answer: Option C Explanation: 12 in octal = 8 + 2, i.e., 10 in decimal. |
2. | Hexadecimal number E is equal to binary number |
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Answer: Option A Explanation: E = 14 in decimal or 1110 (8 + 4 + 2 + 0 = 14) is binary. |
3. | Decimal number 46 in excess 3 code = |
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Answer: Option B Explanation: Decimal 46 in excess 3 code = 46 + 33 = 79 in decimal = 0111 1001 in 4 bit binary. |
4. | Logic hardware is available only in NAND and NOR. |
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Answer: Option B Explanation: Other gates are also available. |
5. | A 4 input AND gate is equivalent to |
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Answer: Option D Explanation: All the switches have to be closed so that the circuit can be made. In AND gate all the inputs have to be high for output to be high. |