Electronics and Communication Engineering - Digital Electronics - Discussion

36. 

7BF16 = __________ 2

[A]. 0111 1011 1110
[B]. 0111 1011 1111
[C]. 0111 1011 0111
[D]. 0111 1011 0011

Answer: Option B

Explanation:

7BF16 = 7 x 162 + 11 x 161 + 15 x 160 = 1983 in decimal = 0111 1011 1111 in binary.


Tharun said: (May 19, 2014)  
In hexadecimal weights are 8-4-2-1.
then,

7 - 0111.
B - 1011(11).
F - 1111(15).

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