Electrical Engineering - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 1)
1.
A 10 
F, 20 F, 22 F, and 100 F capacitor are in parallel. The total capacitance is
F, 20 F, 22 F, and 100 F capacitor are in parallel. The total capacitance is2.43 F
F4.86 F
F100 F
F152 F
FDiscussion:
27 comments Page 1 of 3.
Himansu sekhar swain said:
8 years ago
Here, c1 + c2 + c3 + c4
10 + 20 + 22 + 100 = 152m.
10 + 20 + 22 + 100 = 152m.
(7)
Prashant said:
9 years ago
For series = 1/c1 + 1/c2+ .......
Parallel = c1 + c2+ .......
Parallel = c1 + c2+ .......
(4)
Kulbir said:
9 years ago
Series = 1/c1 + 1c2.
Parallel = c1 + c2.
Parallel = c1 + c2.
(1)
Parmanand said:
1 decade ago
Right answer is 152 because in parallel capacitance circuit. Addition of capacitance value.
SINGARAJA said:
9 years ago
When c connected in parallel Cequ = c1 + c2 + c3 + c4.
Mazar pasha said:
9 years ago
When capacitors are connected in parallel we have to add it C = c1 + c2 + c3 + c4.
= 10 + 20 + 22 + 100.
= 152 micro farad.
= 10 + 20 + 22 + 100.
= 152 micro farad.
Manojkumar said:
9 years ago
Yes, it is 152mf. I agree with you all.
Gajanan Atole said:
10 years ago
C1+C2+C3+C3 = 10+20+22+100.
=152mF.
=152mF.
Rupak sahu said:
1 decade ago
Each capacitance are add so 152 micro Faraday.
Mahalaxmi hiremath said:
1 decade ago
C = c1+c2+c3 = 152.
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