# Electrical Engineering - Capacitors - Discussion

### Discussion :: Capacitors - General Questions (Q.No.1)

1.

A 10 F, 20 F, 22 F, and 100 F capacitor are in parallel. The total capacitance is

 [A]. 2.43 F [B]. 4.86 F [C]. 100 F [D]. 152 F

Explanation:

No answer description available for this question.

 Prashant Telasi said: (Dec 9, 2010) Capacitances are additive when connected in parallel. therefore, C = c1+c2+c3+c4

 Praveen C B said: (Feb 4, 2011) When capacitors are connected in parallel they are like connecting resistors in series so net capacitance=c=c1+c2+c3+c4 =10+20+22+100 =152*10^-6F

 Raj Talwar said: (Apr 13, 2011) Capacitors when connected in parallel can be added for total Capacitance. C=C1+C2+C3+C4 C= 10+20+22+100 C=152Micro Farad

 Karthik said: (Jun 29, 2011) Equavalent capacitance C=C1+C2+C3+C4 Hence C=10+20+22+100 C=152 micro farads

 Abinaya.J said: (Nov 28, 2011) When capacitance are connected in parallel The equation is c=c1+c2+c3+c4 Therefore c=10+20+22+100 c=152 micro farad

 Amiya Ku. Bhoi said: (Dec 13, 2011) c1=10, c2=20, c3=22, c4=100. C= ??? capacitance are connected in parallel, than C=c1+C2+c3+c4 =10+20+22+100 =152 m.farad

 Er. Shyam said: (Dec 18, 2011) Ans. D C= C1+C2+C3+C4 C= 10+20+22+100 C= 152 micro farad

 Ajay Sariya said: (Apr 9, 2012) For equivalent capacitacnce, C=C1+C2+C3+C4 C=10+20+22+100 C=152 micro farad So right answer is D.

 Bhushan-Dj said: (May 31, 2012) Simply resistance added directly in series and capacitance are added directly into parallel. Capacitance=c1+c2+c3+c4. =10+20+22+100. =152uf.

 John said: (Dec 8, 2012) You add capacitors in parallel. Total capacitance=10+20+22+100. 152uF - Right answer.

 Amar Kailas Randhe said: (Jul 30, 2013) While connecting capacitors in parallel we will add them to get right value. i.e., 10+20+22+100 and which is equal to 152 microfarad.

 Bala said: (Aug 2, 2013) It is opposite to that of resistance i.e. In resistors we add them when connected in series. Whereas in capacitors we add them when connected in parallel.

 Pramod Shinva said: (Sep 4, 2013) CT = C1+C2+C3+C4. = 10+20+22+100. = 152 MICRO FARAD. ANSWER IS D.

 Parmanand said: (Nov 23, 2013) Right answer is 152 because in parallel capacitance circuit. Addition of capacitance value.

 Dasi Vinodh said: (Mar 14, 2014) Capacitors series and parallel combination is opposite to the resistors series and parallel connection hence total capacitance in parallel is equal to the sum of all capacitances. i.e C = C1+C2+C3+C4+...+Cn.

 Monuvarshney said: (Mar 26, 2014) Ceq = C1+C2+C3+C4. Ceq = 10+20+22+100 = 152.

 Vikash Yaduvanshi said: (Sep 17, 2014) C = C1+C2+C3+C4....+Cn.

 Prabas said: (Feb 6, 2015) 10+20+22+100=152 why because capacitors series.

 Mahalaxmi Hiremath said: (Feb 26, 2015) C = c1+c2+c3 = 152.

 Rupak Sahu said: (Jul 7, 2015) Each capacitance are add so 152 micro Faraday.

 Gajanan Atole said: (Jan 23, 2016) C1+C2+C3+C3 = 10+20+22+100. =152mF.

 Manojkumar said: (Aug 23, 2016) Yes, it is 152mf. I agree with you all.

 Mazar Pasha said: (Sep 6, 2016) When capacitors are connected in parallel we have to add it C = c1 + c2 + c3 + c4. = 10 + 20 + 22 + 100. = 152 micro farad.

 Singaraja said: (Oct 8, 2016) When c connected in parallel Cequ = c1 + c2 + c3 + c4.

 Kulbir said: (Oct 31, 2016) Series = 1/c1 + 1c2. Parallel = c1 + c2.

 Prashant said: (Nov 25, 2016) For series = 1/c1 + 1/c2+ ....... Parallel = c1 + c2+ .......

 Himansu Sekhar Swain said: (Jun 7, 2017) Here, c1 + c2 + c3 + c4 10 + 20 + 22 + 100 = 152m.