Electrical Engineering - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 1)
1.
A 10
F, 20
F, 22
F, and 100
F capacitor are in parallel. The total capacitance is




Discussion:
27 comments Page 1 of 3.
Dasi vinodh said:
1 decade ago
Capacitors series and parallel combination is opposite to the resistors series and parallel connection hence total capacitance in parallel is equal to the sum of all capacitances. i.e C = C1+C2+C3+C4+...+Cn.
PRAVEEN C B said:
1 decade ago
When capacitors are connected in parallel they are like connecting resistors in series so
net capacitance=c=c1+c2+c3+c4
=10+20+22+100
=152*10^-6F
net capacitance=c=c1+c2+c3+c4
=10+20+22+100
=152*10^-6F
Bala said:
1 decade ago
It is opposite to that of resistance i.e.
In resistors we add them when connected in series.
Whereas in capacitors we add them when connected in parallel.
In resistors we add them when connected in series.
Whereas in capacitors we add them when connected in parallel.
Bhushan-DJ said:
1 decade ago
Simply resistance added directly in series and capacitance are added directly into parallel.
Capacitance=c1+c2+c3+c4.
=10+20+22+100.
=152uf.
Capacitance=c1+c2+c3+c4.
=10+20+22+100.
=152uf.
Amar kailas randhe said:
1 decade ago
While connecting capacitors in parallel we will add them to get right value.
i.e., 10+20+22+100 and which is equal to 152 microfarad.
i.e., 10+20+22+100 and which is equal to 152 microfarad.
Amiya ku. Bhoi said:
1 decade ago
c1=10,
c2=20,
c3=22,
c4=100.
C= ???
capacitance are connected in parallel,
than C=c1+C2+c3+c4
=10+20+22+100
=152 m.farad
c2=20,
c3=22,
c4=100.
C= ???
capacitance are connected in parallel,
than C=c1+C2+c3+c4
=10+20+22+100
=152 m.farad
Mazar pasha said:
9 years ago
When capacitors are connected in parallel we have to add it C = c1 + c2 + c3 + c4.
= 10 + 20 + 22 + 100.
= 152 micro farad.
= 10 + 20 + 22 + 100.
= 152 micro farad.
Raj Talwar said:
1 decade ago
Capacitors when connected in parallel can be added for total Capacitance.
C=C1+C2+C3+C4
C= 10+20+22+100
C=152Micro Farad
C=C1+C2+C3+C4
C= 10+20+22+100
C=152Micro Farad
ABINAYA.J said:
1 decade ago
When capacitance are connected in parallel
The equation is c=c1+c2+c3+c4
Therefore c=10+20+22+100
c=152 micro farad
The equation is c=c1+c2+c3+c4
Therefore c=10+20+22+100
c=152 micro farad
Ajay Sariya said:
1 decade ago
For equivalent capacitacnce,
C=C1+C2+C3+C4
C=10+20+22+100
C=152 micro farad
So right answer is D.
C=C1+C2+C3+C4
C=10+20+22+100
C=152 micro farad
So right answer is D.
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