Electrical Engineering - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 1)
1.
A 10
F, 20
F, 22
F, and 100
F capacitor are in parallel. The total capacitance is




Discussion:
27 comments Page 2 of 3.
Prashant Telasi said:
1 decade ago
Capacitances are additive when connected in parallel.
therefore,
C = c1+c2+c3+c4
therefore,
C = c1+c2+c3+c4
Parmanand said:
1 decade ago
Right answer is 152 because in parallel capacitance circuit. Addition of capacitance value.
John said:
1 decade ago
You add capacitors in parallel.
Total capacitance=10+20+22+100.
152uF - Right answer.
Total capacitance=10+20+22+100.
152uF - Right answer.
Karthik said:
1 decade ago
Equavalent capacitance C=C1+C2+C3+C4
Hence C=10+20+22+100
C=152 micro farads
Hence C=10+20+22+100
C=152 micro farads
PRAMOD SHINVA said:
1 decade ago
CT = C1+C2+C3+C4.
= 10+20+22+100.
= 152 MICRO FARAD.
ANSWER IS D.
= 10+20+22+100.
= 152 MICRO FARAD.
ANSWER IS D.
Prashant said:
9 years ago
For series = 1/c1 + 1/c2+ .......
Parallel = c1 + c2+ .......
Parallel = c1 + c2+ .......
(4)
Er. Shyam said:
1 decade ago
Ans. D
C= C1+C2+C3+C4
C= 10+20+22+100
C= 152 micro farad
C= C1+C2+C3+C4
C= 10+20+22+100
C= 152 micro farad
SINGARAJA said:
9 years ago
When c connected in parallel Cequ = c1 + c2 + c3 + c4.
Himansu sekhar swain said:
8 years ago
Here, c1 + c2 + c3 + c4
10 + 20 + 22 + 100 = 152m.
10 + 20 + 22 + 100 = 152m.
(7)
Prabas said:
1 decade ago
10+20+22+100=152 why because capacitors series.
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