Electrical Engineering - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 1)
1.
A 10 
F, 20 F, 22 F, and 100 F capacitor are in parallel. The total capacitance is
F, 20 F, 22 F, and 100 F capacitor are in parallel. The total capacitance is2.43 F
F4.86 F
F100 F
F152 F
FDiscussion:
27 comments Page 3 of 3.
Ajay Sariya said:
1 decade ago
For equivalent capacitacnce,
C=C1+C2+C3+C4
C=10+20+22+100
C=152 micro farad
So right answer is D.
C=C1+C2+C3+C4
C=10+20+22+100
C=152 micro farad
So right answer is D.
Er. Shyam said:
1 decade ago
Ans. D
C= C1+C2+C3+C4
C= 10+20+22+100
C= 152 micro farad
C= C1+C2+C3+C4
C= 10+20+22+100
C= 152 micro farad
Amiya ku. Bhoi said:
1 decade ago
c1=10,
c2=20,
c3=22,
c4=100.
C= ???
capacitance are connected in parallel,
than C=c1+C2+c3+c4
=10+20+22+100
=152 m.farad
c2=20,
c3=22,
c4=100.
C= ???
capacitance are connected in parallel,
than C=c1+C2+c3+c4
=10+20+22+100
=152 m.farad
ABINAYA.J said:
1 decade ago
When capacitance are connected in parallel
The equation is c=c1+c2+c3+c4
Therefore c=10+20+22+100
c=152 micro farad
The equation is c=c1+c2+c3+c4
Therefore c=10+20+22+100
c=152 micro farad
Karthik said:
1 decade ago
Equavalent capacitance C=C1+C2+C3+C4
Hence C=10+20+22+100
C=152 micro farads
Hence C=10+20+22+100
C=152 micro farads
Raj Talwar said:
1 decade ago
Capacitors when connected in parallel can be added for total Capacitance.
C=C1+C2+C3+C4
C= 10+20+22+100
C=152Micro Farad
C=C1+C2+C3+C4
C= 10+20+22+100
C=152Micro Farad
PRAVEEN C B said:
1 decade ago
When capacitors are connected in parallel they are like connecting resistors in series so
net capacitance=c=c1+c2+c3+c4
=10+20+22+100
=152*10^-6F
net capacitance=c=c1+c2+c3+c4
=10+20+22+100
=152*10^-6F
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers