Civil Engineering - Concrete Technology - Discussion
Discussion Forum : Concrete Technology - Section 2 (Q.No. 44)
44.
If the depth of moist sand in a cylinder is 15 cm and the depth of the sand when fully inundated with water is 12 cm, the bulking of the moist sand, is
Discussion:
14 comments Page 1 of 2.
Gururaj said:
1 decade ago
Formula = {(h-h1)/h1)}*100, h = 15, h1 = 12.
= {(15-12)/12}*100,
= (3/12)*100,
= 0.25*100,
= 25%.
= {(15-12)/12}*100,
= (3/12)*100,
= 0.25*100,
= 25%.
(1)
SHYAM said:
10 years ago
15 - 12/12*100 = 25%
(1)
Sai said:
9 years ago
Thanks for providing the explanation of the solution.
(1)
Haris said:
8 years ago
Here, 15 - 12/12*100 = 25%.
(1)
Vijay said:
8 years ago
What's this formula for this?
(1)
Mounica said:
8 years ago
Formula isn't required.
It's % bulking of sand = what percentage of inundated sand, the bulking happened.
Therefore, = (bulked mass / inundated mass)*100.
= (15-12)*100/12.
= 25%.
It's % bulking of sand = what percentage of inundated sand, the bulking happened.
Therefore, = (bulked mass / inundated mass)*100.
= (15-12)*100/12.
= 25%.
(1)
Jay said:
5 years ago
Thanks for explaining it.
(1)
Ganesh said:
4 years ago
The Correct answer is 20% !! 3/15*100 not 3/12!.
(1)
Deepak raj joshi said:
2 months ago
The initial depth of sand = 12cm,
The final depth of sand after bulking = 15 cm,
bulked depth = 15-12 =3 cm,
Hence, bulking of moist sand and the initial depth is;
= 3cm/12cm * 100% = 25%.
The final depth of sand after bulking = 15 cm,
bulked depth = 15-12 =3 cm,
Hence, bulking of moist sand and the initial depth is;
= 3cm/12cm * 100% = 25%.
(1)
Sanjeevi.s said:
1 decade ago
Moist sand h = 15cm.
Saturated of sand h1 = 12.
Formula is h-h1/hi*100.
= 15-12/15*100.
= 25%.
Saturated of sand h1 = 12.
Formula is h-h1/hi*100.
= 15-12/15*100.
= 25%.
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