Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 2 (Q.No. 44)
44.
If the depth of moist sand in a cylinder is 15 cm and the depth of the sand when fully inundated with water is 12 cm, the bulking of the moist sand, is
10%
12%
15%
20%
25%.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
14 comments Page 1 of 2.

Deepak raj joshi said:   2 months ago
The initial depth of sand = 12cm,
The final depth of sand after bulking = 15 cm,
bulked depth = 15-12 =3 cm,
Hence, bulking of moist sand and the initial depth is;
= 3cm/12cm * 100% = 25%.
(1)

WASEEM SANGI said:   3 years ago
We can solve it simply as;

Dry volume and inundated volume are equal so the original volume of sand is 12 cm
12cm = 100% volume of given sample.
3cm = 100/4 = 25cm.

The sand bulks by 3cm and depth become 15cm which is 3cm greater than the original depth so bulking of sand is 3cm or 25%.

Ganesh said:   4 years ago
The Correct answer is 20% !! 3/15*100 not 3/12!.
(1)

Jay said:   5 years ago
Thanks for explaining it.
(1)

Mounica said:   8 years ago
Formula isn't required.

It's % bulking of sand = what percentage of inundated sand, the bulking happened.

Therefore, = (bulked mass / inundated mass)*100.

= (15-12)*100/12.

= 25%.
(1)

Vijay said:   8 years ago
What's this formula for this?
(1)

Haris said:   8 years ago
Here, 15 - 12/12*100 = 25%.
(1)

Sai said:   9 years ago
Thanks for providing the explanation of the solution.
(1)

SHYAM said:   10 years ago
15 - 12/12*100 = 25%
(1)

Kamran said:   10 years ago
Thanks to all improving our knowledge.


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