Civil Engineering - Concrete Technology - Discussion

Discussion Forum : Concrete Technology - Section 2 (Q.No. 44)
44.
If the depth of moist sand in a cylinder is 15 cm and the depth of the sand when fully inundated with water is 12 cm, the bulking of the moist sand, is
10%
12%
15%
20%
25%.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
14 comments Page 1 of 2.

WASEEM SANGI said:   3 years ago
We can solve it simply as;

Dry volume and inundated volume are equal so the original volume of sand is 12 cm
12cm = 100% volume of given sample.
3cm = 100/4 = 25cm.

The sand bulks by 3cm and depth become 15cm which is 3cm greater than the original depth so bulking of sand is 3cm or 25%.

Deepak raj joshi said:   2 months ago
The initial depth of sand = 12cm,
The final depth of sand after bulking = 15 cm,
bulked depth = 15-12 =3 cm,
Hence, bulking of moist sand and the initial depth is;
= 3cm/12cm * 100% = 25%.
(1)

Mounica said:   8 years ago
Formula isn't required.

It's % bulking of sand = what percentage of inundated sand, the bulking happened.

Therefore, = (bulked mass / inundated mass)*100.

= (15-12)*100/12.

= 25%.
(1)

Sanjeevi.s said:   1 decade ago
Moist sand h = 15cm.
Saturated of sand h1 = 12.

Formula is h-h1/hi*100.

= 15-12/15*100.

= 25%.

Gururaj said:   1 decade ago
Formula = {(h-h1)/h1)}*100, h = 15, h1 = 12.

= {(15-12)/12}*100,
= (3/12)*100,
= 0.25*100,
= 25%.
(1)

Nitin said:   1 decade ago
15-12/15*100 shall comes 20 %, so the option should be D.

Sai said:   9 years ago
Thanks for providing the explanation of the solution.
(1)

Prashant jadhav said:   1 decade ago
Formula = ((h-h1)/h1)*100.
= 25%.

Ganesh said:   4 years ago
The Correct answer is 20% !! 3/15*100 not 3/12!.
(1)

Kamran said:   10 years ago
Thanks to all improving our knowledge.


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