Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
174 comments Page 9 of 18.
Lak verma said:
1 decade ago
Time not given in question so let it (X) then
Speed*time=distance
14x -10x=20
X=5 hr
So 10*5=50km question asking for distance
Speed*time=distance
14x -10x=20
X=5 hr
So 10*5=50km question asking for distance
Priya said:
1 year ago
According to me;
Here d1-d2 = 14km/h-10km/h=4km/h
Now 4 unit = 20.
Then 1 unit = 5.
Then the actual distance is 10*5 = 50km.
Here d1-d2 = 14km/h-10km/h=4km/h
Now 4 unit = 20.
Then 1 unit = 5.
Then the actual distance is 10*5 = 50km.
(66)
Tanay said:
1 decade ago
In 4 kmph he walk more 20 km.
So in 1 kmph he walks (20/4) =5 km.
Thus in 10 kmph he walks (5*10) =50 km (actual distance).
So in 1 kmph he walks (20/4) =5 km.
Thus in 10 kmph he walks (5*10) =50 km (actual distance).
Pulyala ajith kumar said:
2 years ago
The difference between distances is 20km and d = s * t.
So 14x-10x = 20.
x = 5hrs
The actual distance is s*t = 10 * 5 = 50km.
So 14x-10x = 20.
x = 5hrs
The actual distance is s*t = 10 * 5 = 50km.
(55)
Satya said:
9 years ago
Given;
14kmph at 20 km MORE i.e extra speed.
So we can write it as 4 kmph -20.,
Each km 20÷4 = 5.
Hence 10 * 5 = 50.
14kmph at 20 km MORE i.e extra speed.
So we can write it as 4 kmph -20.,
Each km 20÷4 = 5.
Hence 10 * 5 = 50.
Amit said:
6 years ago
The correct answer should be 70 as the value of x is 50 at the speed of 10 km/hr but at the speed of 14 km hr is 20 more.
Bhat said:
1 decade ago
Difference between distance i.e. 14-10 = 4.
Now calculate avg distance i.e. 20/4 = 5.
Now actual distance = 10*f = 50.
Now calculate avg distance i.e. 20/4 = 5.
Now actual distance = 10*f = 50.
Rayan said:
6 years ago
The another method.
Let's, time will be t.
so, 14t-10t=20,
or. 4t=20,
or, t=5.
so, the total distance is 5*0 = 50.
Let's, time will be t.
so, 14t-10t=20,
or. 4t=20,
or, t=5.
so, the total distance is 5*0 = 50.
Sagar said:
5 years ago
Hi, whenever the time is constant we can equate the distance ratio to speed ratio. That is 10/14 =x/x+20 then x=50.
Chahat Mishra said:
9 months ago
Very easy approach:
Here d1 - d2 = 14 - 10 = 4km/h.
Now 4 = 20.
Then 1 = 5.
The actual distance is 10 * 5 = 50km.
Here d1 - d2 = 14 - 10 = 4km/h.
Now 4 = 20.
Then 1 = 5.
The actual distance is 10 * 5 = 50km.
(131)
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