Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
174 comments Page 8 of 18.
Kunal said:
10 years ago
First calculate as:
Time = Distance/Speed = 20 km/14-10 kmph = 20/4 = 5 hr.
Means time = 5 hr.
Distance = Time*Actual speed.
Distance = 5*10 = 50 km.
Time = Distance/Speed = 20 km/14-10 kmph = 20/4 = 5 hr.
Means time = 5 hr.
Distance = Time*Actual speed.
Distance = 5*10 = 50 km.
Parth singh said:
5 years ago
Here time is constant.
S, the o formula for time is Distance /Speed.
10/x = 14/x+200.
Equate this we will find:
10x + 200 = 14x,
4x = 200,
X = 50.
S, the o formula for time is Distance /Speed.
10/x = 14/x+200.
Equate this we will find:
10x + 200 = 14x,
4x = 200,
X = 50.
Vishal said:
2 years ago
Why t in both the equation is same?
If a person is walking at 14km/hr then it will take less time then 10km/hr, which means both t are different.
If a person is walking at 14km/hr then it will take less time then 10km/hr, which means both t are different.
(12)
Jason Valentine said:
1 year ago
His actual speed is 10 km/h and from the given question.
14x-10x = 20,
4x = 20,
x = 5 hours.
Then the actual distance will be;
10 * 5 = 50 km.
14x-10x = 20,
4x = 20,
x = 5 hours.
Then the actual distance will be;
10 * 5 = 50 km.
(48)
Md. Palash said:
5 years ago
The difference per hour is 14 - 10 = 4 km.
So, the time taken to travel 20 km is = 20/4 = 5 hours.
Now, the actual distance = 10 * 5 = 50 km.
So, the time taken to travel 20 km is = 20/4 = 5 hours.
Now, the actual distance = 10 * 5 = 50 km.
MO HASAN said:
2 years ago
His actual speed is 10 km/h and from given question.
14x-10x = 20,
4x = 20,
x = 5 hours.
then the actual distance will be;
10*5 = 50 km.
14x-10x = 20,
4x = 20,
x = 5 hours.
then the actual distance will be;
10*5 = 50 km.
(94)
Hemanth said:
10 years ago
Here in this question both the times are equal. So we use s1/d1 = s2/d2.
Therefore: 10/x = 14/x+20.
10x+200 = 14x.
4x = 200.
x = 50.
Therefore: 10/x = 14/x+20.
10x+200 = 14x.
4x = 200.
x = 50.
White said:
8 years ago
The actual distance 50km(10km) but he travelled 70km by 14kmph, the question is THE ACTUAL DISTANCE TRAVELLED BY HIM? Is it 70 or 50?
Parikshit said:
8 years ago
If 10kmph will cover x distance than 14 will cover it faster. But why here 20 km is added to 14kmph distance. How can it be possible?
Sandeep jayker said:
6 years ago
Distance= (a/x-y) * y.
a=20km
X=14 KMPH.
Y=10 KMPH.
(20KM/14KMPH-10KMPH) * 10KMPH.
(20KM/4KMPH) * 10KMPH.
So, the answer is 50KM.
a=20km
X=14 KMPH.
Y=10 KMPH.
(20KM/14KMPH-10KMPH) * 10KMPH.
(20KM/4KMPH) * 10KMPH.
So, the answer is 50KM.
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