Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
174 comments Page 5 of 18.
Kinnari said:
1 decade ago
It goes by the formula S=D/T (Speed = Distance/Time)
So, T = D/S => T=x/10 ............(1)
T = x+20/14 .........(2)
Taking both the times together we get frm (1) and (2)
x/10=x+20/14
Now solve it as shown above. Hope you get it now.
So, T = D/S => T=x/10 ............(1)
T = x+20/14 .........(2)
Taking both the times together we get frm (1) and (2)
x/10=x+20/14
Now solve it as shown above. Hope you get it now.
(1)
Manish Kumar said:
8 years ago
Hello friends.
The person walks 14kmph instead of 10 km that means his original speed is 10kmph.
By walking 4kmph extra speed he covers 20 km.
That means for 1kmph he will cover 5 km.
Then for 10kmph, he will go 50 km. It's so simple.
The person walks 14kmph instead of 10 km that means his original speed is 10kmph.
By walking 4kmph extra speed he covers 20 km.
That means for 1kmph he will cover 5 km.
Then for 10kmph, he will go 50 km. It's so simple.
Aryan said:
2 years ago
@All,
According to me, the solution is;
For every 1 km/hr there is 5 km distance travelled;
So for 10km/hr there is 50km distance travelled;
which means for 4 more km/hr in question there is 20 kM distance.
So, for 10 km it's 50 km.
According to me, the solution is;
For every 1 km/hr there is 5 km distance travelled;
So for 10km/hr there is 50km distance travelled;
which means for 4 more km/hr in question there is 20 kM distance.
So, for 10 km it's 50 km.
(10)
Selvam said:
1 decade ago
Hey anu see cross multiplication
So,
x/10=(x+20)/14
first multiply the (x+20) by 10 and u ill get 10x+200
second multiply the x by 14 so u ill get 14x
now 14x=10x+200
14x-10x=200
4x=200
x=200/4
x=50
I hope you will understand this.
So,
x/10=(x+20)/14
first multiply the (x+20) by 10 and u ill get 10x+200
second multiply the x by 14 so u ill get 14x
now 14x=10x+200
14x-10x=200
4x=200
x=200/4
x=50
I hope you will understand this.
Manish said:
8 years ago
If he travels xkm.
He would have travelled with the speed of 10km/hr. Thus time=>x10.
But he travels with 14km/hr and thus he travels extra 20km => x+20 km. Thus time=>x+20/14
Equating both,
X/10=x+20/14.
You will get 50.
He would have travelled with the speed of 10km/hr. Thus time=>x10.
But he travels with 14km/hr and thus he travels extra 20km => x+20 km. Thus time=>x+20/14
Equating both,
X/10=x+20/14.
You will get 50.
Kiran said:
1 decade ago
If this person walks 10km then he walks xkm.
If this person walks 14 km then he will be walks x + 20 km.
Then 10 kmph -> x km.
&14 kmph -> x + 20 km.
So 10 * (x + 20) = 14 * x.
10x + 200 = 14x.
4x = 200.
x = 50 km.
If this person walks 14 km then he will be walks x + 20 km.
Then 10 kmph -> x km.
&14 kmph -> x + 20 km.
So 10 * (x + 20) = 14 * x.
10x + 200 = 14x.
4x = 200.
x = 50 km.
Mr.Dims said:
5 years ago
The Right answer is 70km.
Actually, he thinks that he needs to travel 10km/hr but he travelled 14km/hr.
In this case, he travelled extra 4km/hr, but finally, he travelled 20km extra.
So actual 50km+extra travelled 20km, total 70KM.
Actually, he thinks that he needs to travel 10km/hr but he travelled 14km/hr.
In this case, he travelled extra 4km/hr, but finally, he travelled 20km extra.
So actual 50km+extra travelled 20km, total 70KM.
(1)
Naviyaashree KA said:
1 month ago
If he is going at 10km/hr the distance is 10*t.
If he is going at 14km/hr the distance is 14*t.
The difference = 20km
14t-10t = 20
4t = 20
t = 5 hours
Now, actual distance = 10 * 5.
= 50 km.
If he is going at 14km/hr the distance is 14*t.
The difference = 20km
14t-10t = 20
4t = 20
t = 5 hours
Now, actual distance = 10 * 5.
= 50 km.
(11)
Vikash said:
9 years ago
Let actual distance x km.
Actual speed =10 kmph T1 = ?
Man walk 20 km more,
Distance = x + 20.
Speed = 14 kmph T2 = ?
Now T1 = T2.
D1/S1 = D2/S2.
x/10 = x + 20/14 after solving x (actual distance) = 50 km answer.
Actual speed =10 kmph T1 = ?
Man walk 20 km more,
Distance = x + 20.
Speed = 14 kmph T2 = ?
Now T1 = T2.
D1/S1 = D2/S2.
x/10 = x + 20/14 after solving x (actual distance) = 50 km answer.
Manu M said:
7 years ago
@All.
The actual distance travelled is 70 Km instead of 50 km. If he travels in 10 Kph distance should be 50, but he walks at a speed of 14 kph. So the actual distance is 70 Kph. Please correct me if any corrections.
The actual distance travelled is 70 Km instead of 50 km. If he travels in 10 Kph distance should be 50, but he walks at a speed of 14 kph. So the actual distance is 70 Kph. Please correct me if any corrections.
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