Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
174 comments Page 4 of 18.
Sriram.g said:
6 years ago
Both are travelling at different speed but in the same amount of time.
So, if x is the distance travelled by A, then the time taken by A is x/10. then time = distance/speed.
And time taken by B is (x+20)/14.
Both A and B took same time so x/10=(x+20)/14.
By solving we get x=50.
So, if x is the distance travelled by A, then the time taken by A is x/10. then time = distance/speed.
And time taken by B is (x+20)/14.
Both A and B took same time so x/10=(x+20)/14.
By solving we get x=50.
Hroshid said:
8 years ago
Suppose walking time of this man = t.
So the walking distance for 14kmph = 14 * t = 14t,
and the actual walking distance=10 * t = 10t.
So as question, we can say 14t-10t = 20km # 4t=20 #t=5.
So the actual distance travel by him = 10 * 5 = 50km.
Hope all of you understand.
So the walking distance for 14kmph = 14 * t = 14t,
and the actual walking distance=10 * t = 10t.
So as question, we can say 14t-10t = 20km # 4t=20 #t=5.
So the actual distance travel by him = 10 * 5 = 50km.
Hope all of you understand.
Krishna said:
1 decade ago
I agree with gautam .... the time is not constant in both cases.
So it is false ..... how to equate them
He travels at 10km/hr and walks d km in t1 hrs
Similarly, he travels at 14km/hr and walks (d+20)km in t2 hrs
How can u equate t1 and t2? It is not given.
So it is false ..... how to equate them
He travels at 10km/hr and walks d km in t1 hrs
Similarly, he travels at 14km/hr and walks (d+20)km in t2 hrs
How can u equate t1 and t2? It is not given.
Anjith said:
1 decade ago
Hi,
The man travels at a speed of 14, but he assumed to travel at a speed of 10 kmph.
Means the man covered 70km, but he assumed to cover is 50 km.
Hence the actual distance covered by the man is 70 kms, and it is the answer.
Please let me know if I am wrong.
The man travels at a speed of 14, but he assumed to travel at a speed of 10 kmph.
Means the man covered 70km, but he assumed to cover is 50 km.
Hence the actual distance covered by the man is 70 kms, and it is the answer.
Please let me know if I am wrong.
Arun said:
6 years ago
It's based on per hour that means time is constant. And when time is constant distance and speed will be directly proportional.
Speed : 14 : 10
=> 7:5.
Since distance is directly proportional.
Its ratio also will be 7:5
20 more means the difference of 7-5.
Speed : 14 : 10
=> 7:5.
Since distance is directly proportional.
Its ratio also will be 7:5
20 more means the difference of 7-5.
Bhajan Lal said:
2 weeks ago
If he is going at 10km/hr the distance is 10*t.
If he is going at 14km/hr the distance is 14*t.
The difference = 20km.
14t-10t = 20,
4t = 20.
t = 5 hours.
Now, actual distance = 10 * 5.
= 50 km.
But,
The actual distance travelled by him is : 14 * 5 = 70 Km.
If he is going at 14km/hr the distance is 14*t.
The difference = 20km.
14t-10t = 20,
4t = 20.
t = 5 hours.
Now, actual distance = 10 * 5.
= 50 km.
But,
The actual distance travelled by him is : 14 * 5 = 70 Km.
(2)
Shivani k said:
7 years ago
The question says that if he travelled 14km/hr instead of 10km/hr he would cover 20km more so
(14 -10)= 4 km/hr.
Distance covered with speed of 4km/hr=20km.
1km/hr= 20/4,
= 5km.
Actual distance covered with 10km/hr.
10 * 5 =50 km.
(14 -10)= 4 km/hr.
Distance covered with speed of 4km/hr=20km.
1km/hr= 20/4,
= 5km.
Actual distance covered with 10km/hr.
10 * 5 =50 km.
Varsha said:
4 years ago
Instead of 10 kmph he is walking 14kmph which means he is walking 4 kmph more and totally he walks 20 km.
Hence, 20/4=5.
If we take this for 10 kmph then x it by 5 which means 5* 50= 50kmph.
Can anyone tell me whether we can solve it like this?
Hence, 20/4=5.
If we take this for 10 kmph then x it by 5 which means 5* 50= 50kmph.
Can anyone tell me whether we can solve it like this?
(1)
Salsabil said:
3 years ago
According to me, by using the simple formula we can iterate lucidly like this way,
Let the time be x hours
According to the question;
14x - 10x = 20
4x = 20
x = 5 hours.
His actual speed is 10 km/h.
So, the actual distance is 10 * 5 = 50 km.
Let the time be x hours
According to the question;
14x - 10x = 20
4x = 20
x = 5 hours.
His actual speed is 10 km/h.
So, the actual distance is 10 * 5 = 50 km.
(207)
Sonia said:
9 years ago
Time is considered as equal in both cases because of its average speed. Look over the question again. Speed is 14kmph & 10 kmph. It means 14 km travelled in one hour and 10 km travelled in one hour. So the time in both cases is the same.
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