Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
Then, | x | = | x + 20 |
10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
174 comments Page 6 of 18.
Kamal said:
5 years ago
Present speed = 14 km/h & Regular speed =10 km/h.
Difference of speed =14- 10 km/h = 4 km/h.
That means;
If his speed more 4 km/h he completes 20 km.
If he runs at his usual he complete = 20/5) * 10 km = 50 km.
Difference of speed =14- 10 km/h = 4 km/h.
That means;
If his speed more 4 km/h he completes 20 km.
If he runs at his usual he complete = 20/5) * 10 km = 50 km.
TAMIL SELVAN said:
1 year ago
By ratio method, if time is constant speed is directly proportional to distance so;
speed: 10 : 14.
distance : 10x : 14x.
difference btw (10x-14x) = 4x.
4x = 20,
x = 5.
Put this in the usual speed 10x= 10*5=50 km.
speed: 10 : 14.
distance : 10x : 14x.
difference btw (10x-14x) = 4x.
4x = 20,
x = 5.
Put this in the usual speed 10x= 10*5=50 km.
(117)
Krishna Sharma said:
9 years ago
Please solve this.
While covering a distance of 60 km, A takes 4 hours more than B. If A doubles its speed, A took 2 hours less than B. Find the walking speed using a simultaneous equation or quadratic equation.
While covering a distance of 60 km, A takes 4 hours more than B. If A doubles its speed, A took 2 hours less than B. Find the walking speed using a simultaneous equation or quadratic equation.
Ramu Dhakal said:
7 years ago
Time = Distance/Speed.
For 10km/h,
T=D/S.
Let the actual distance be x.
Therefore T= x/10 -------> Eq 1
For 14km/h,
T=D/S
T= x+20/14 ------> Eq 2
By equation 1 and 2.
x/10=x+20/14,
x=50.
For 10km/h,
T=D/S.
Let the actual distance be x.
Therefore T= x/10 -------> Eq 1
For 14km/h,
T=D/S
T= x+20/14 ------> Eq 2
By equation 1 and 2.
x/10=x+20/14,
x=50.
Liashee said:
3 years ago
D= (S1*T ) - (S2*T)
20= (14*T) - (10*T)
20= 14T - 10T
T = 20/4
T= 5 hrs.
Therefore Actual distance where actual speed was 10km/ hr.
D= S*T
= 10km/hr * 5hr.
= 50km.
I hope this was helpful.
20= (14*T) - (10*T)
20= 14T - 10T
T = 20/4
T= 5 hrs.
Therefore Actual distance where actual speed was 10km/ hr.
D= S*T
= 10km/hr * 5hr.
= 50km.
I hope this was helpful.
(32)
Dharma said:
4 years ago
S=14km/hr d=20km
T=d/s, So, 14/20= 5hrs,
Now we have T=5hrs and s=10km/hr is the actual speed he needs to go.
S=10 T=5
Now, d= S x T.
=10*-5.
= 50 km.
That's all.
T=d/s, So, 14/20= 5hrs,
Now we have T=5hrs and s=10km/hr is the actual speed he needs to go.
S=10 T=5
Now, d= S x T.
=10*-5.
= 50 km.
That's all.
Muneer said:
1 decade ago
Let distance travelled be x,
Since the time taken is same here so,
time taken to walk 14 km more at speed 14 kmph =time taken to walk the distance at speed 10 kmph
(x+20)/14=x/10
5x+100=7x
2x=100
x=50
Since the time taken is same here so,
time taken to walk 14 km more at speed 14 kmph =time taken to walk the distance at speed 10 kmph
(x+20)/14=x/10
5x+100=7x
2x=100
x=50
Ramachandra said:
1 year ago
Let,
Actual dist = X(at-10km\hr).
x/10 = x + 20/14,
14x = 10x + 20,
14x - 10x = 20,
4x = 20,
x = 20/4,
x = 5.
The actual distance at 10kmph * actual distance.
= 10 * 5,
= 50km.
So, the answer is 50km.
Actual dist = X(at-10km\hr).
x/10 = x + 20/14,
14x = 10x + 20,
14x - 10x = 20,
4x = 20,
x = 20/4,
x = 5.
The actual distance at 10kmph * actual distance.
= 10 * 5,
= 50km.
So, the answer is 50km.
(8)
Mayur jaiwal said:
8 years ago
14-10 = 4km,
10*20 = 200,
200%4 = 50.
10*20 = 200,
200%4 = 50.
Keerthi said:
1 decade ago
First the question is find actual distance.
Then given: speed 14 kmph and 10 kmph .
T=D/S.
Actual distance is considered:x.
T=x/10,x+20/14.
x/10=x+20/14.
Then simplify the equation answer is 50.
Then given: speed 14 kmph and 10 kmph .
T=D/S.
Actual distance is considered:x.
T=x/10,x+20/14.
x/10=x+20/14.
Then simplify the equation answer is 50.
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