Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
176 comments Page 5 of 18.
Sneha said:
7 years ago
You have found the result for actual distance (i.e. x) and they said at 14km/he would walk 20km more. So we should do x+20(i.e. 50+20) right? We get 70km.
(1)
Jinia siga said:
6 years ago
I do not understand why x+20 has taken in solution?
(1)
Sirisha said:
6 years ago
14x-10x=20,
4x=20,
X=5.
10*5=50km.
4x=20,
X=5.
10*5=50km.
(1)
Mr.Dims said:
6 years ago
The Right answer is 70km.
Actually, he thinks that he needs to travel 10km/hr but he travelled 14km/hr.
In this case, he travelled extra 4km/hr, but finally, he travelled 20km extra.
So actual 50km+extra travelled 20km, total 70KM.
Actually, he thinks that he needs to travel 10km/hr but he travelled 14km/hr.
In this case, he travelled extra 4km/hr, but finally, he travelled 20km extra.
So actual 50km+extra travelled 20km, total 70KM.
(1)
Bhavesh Solanki said:
5 years ago
14km/hr - 10 km/hr = 4 km/hr(difference)
4km/hr - 20km,
10km/hr (?),
= 10*20/4.
= 50km.
4km/hr - 20km,
10km/hr (?),
= 10*20/4.
= 50km.
(1)
Varsha said:
5 years ago
Instead of 10 kmph he is walking 14kmph which means he is walking 4 kmph more and totally he walks 20 km.
Hence, 20/4=5.
If we take this for 10 kmph then x it by 5 which means 5* 50= 50kmph.
Can anyone tell me whether we can solve it like this?
Hence, 20/4=5.
If we take this for 10 kmph then x it by 5 which means 5* 50= 50kmph.
Can anyone tell me whether we can solve it like this?
(1)
Abc said:
4 years ago
Thanks @Kinnari.
(1)
Nitesh said:
2 decades ago
@Gowtham
But it is not written that time instance is same.
But it is not written that time instance is same.
Savitha said:
2 decades ago
I am not clear with the explanation and I didn't understand this step x/10=x+20/14.
Krishna said:
2 decades ago
I agree with gautam .... the time is not constant in both cases.
So it is false ..... how to equate them
He travels at 10km/hr and walks d km in t1 hrs
Similarly, he travels at 14km/hr and walks (d+20)km in t2 hrs
How can u equate t1 and t2? It is not given.
So it is false ..... how to equate them
He travels at 10km/hr and walks d km in t1 hrs
Similarly, he travels at 14km/hr and walks (d+20)km in t2 hrs
How can u equate t1 and t2? It is not given.
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