Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
174 comments Page 5 of 18.
Nitesh said:
1 decade ago
@Gowtham
But it is not written that time instance is same.
But it is not written that time instance is same.
Savitha said:
1 decade ago
I am not clear with the explanation and I didn't understand this step x/10=x+20/14.
Krishna said:
1 decade ago
I agree with gautam .... the time is not constant in both cases.
So it is false ..... how to equate them
He travels at 10km/hr and walks d km in t1 hrs
Similarly, he travels at 14km/hr and walks (d+20)km in t2 hrs
How can u equate t1 and t2? It is not given.
So it is false ..... how to equate them
He travels at 10km/hr and walks d km in t1 hrs
Similarly, he travels at 14km/hr and walks (d+20)km in t2 hrs
How can u equate t1 and t2? It is not given.
Ankit said:
1 decade ago
Thanks kinnari. I got it.
Muneer said:
1 decade ago
Let distance travelled be x,
Since the time taken is same here so,
time taken to walk 14 km more at speed 14 kmph =time taken to walk the distance at speed 10 kmph
(x+20)/14=x/10
5x+100=7x
2x=100
x=50
Since the time taken is same here so,
time taken to walk 14 km more at speed 14 kmph =time taken to walk the distance at speed 10 kmph
(x+20)/14=x/10
5x+100=7x
2x=100
x=50
Xyz said:
1 decade ago
Why did you take time same in both the cases?
Santosh said:
1 decade ago
I got you Gowtham you expressed very clearly thnks 4 your expalnation.
Ilesh said:
1 decade ago
Just think more here extra 4km/h speed made him to cover extra 20km right,
den
4km/h is........20km(it clearly tells 1km/h is..5km)
10km/h is.......?(10*5=50km)
den
4km/h is........20km(it clearly tells 1km/h is..5km)
10km/h is.......?(10*5=50km)
Gowthami said:
1 decade ago
Thanx illesh. I got it.
Kiran said:
1 decade ago
Time = Distance / Speed
Let Distance = x
First Case : Person's usual speed is 10km/hr
So, T = D/S and putting the values in formula we get : T = x/10
Second case : if he travels at the speed of 14km/hr then he would have walked 20 km more.
We have already assumed distance as x and now in second case we have 20 km more So:
T=D/S, x+20/14
So, we have:
x/10 = x+20/14
And solving the above ,we get
14x = 10x+200
14x - 10x = 200
4x = 200
x = 50Km
Let Distance = x
First Case : Person's usual speed is 10km/hr
So, T = D/S and putting the values in formula we get : T = x/10
Second case : if he travels at the speed of 14km/hr then he would have walked 20 km more.
We have already assumed distance as x and now in second case we have 20 km more So:
T=D/S, x+20/14
So, we have:
x/10 = x+20/14
And solving the above ,we get
14x = 10x+200
14x - 10x = 200
4x = 200
x = 50Km
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