Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
50 km
56 km
70 km
80 km
Answer: Option
Explanation:

Let the actual distance travelled be x km.

Then, x = x + 20
10 14

14x = 10x + 200

4x = 200

x = 50 km.

Discussion:
174 comments Page 6 of 18.

Krishna reddy.gongati said:   1 decade ago
I am not clear with the explanation and I didn't understand this step x/10=x+20/14.

Anu said:   1 decade ago
How we get the 200 here? In this answer please help me in this case.

Selvam said:   1 decade ago
Hey anu see cross multiplication

So,
x/10=(x+20)/14
first multiply the (x+20) by 10 and u ill get 10x+200
second multiply the x by 14 so u ill get 14x
now 14x=10x+200
14x-10x=200
4x=200
x=200/4
x=50

I hope you will understand this.

Harpreet Kaur said:   1 decade ago
I liked the explanation given by Kinnari. I thank you for that.

Arti said:   1 decade ago
Thanks to ilesh I got it.

Lak verma said:   1 decade ago
Time not given in question so let it (X) then
Speed*time=distance
14x -10x=20
X=5 hr
So 10*5=50km question asking for distance

Rahul said:   1 decade ago
The question is asked to find out the distance traveled by the person, and its clearly written he traveled 20km more so we equate it as (x+20) as the distance traveled by him and then when we get the value of X to be 50km. Why it is not added by 20km to get final answer as 70km ?

Jayaraj said:   1 decade ago
Kinnari's explanation is simple and good.

Thirumoorthy Lalapet Karur(DT) said:   1 decade ago
Note: That in both speed Time will be same so

for speed 10km/hr speed=distance/time
10 =x/time1
for speed 14km/hr 14 =(x+20)/time2

: Note time will be same so we equate these two equations respect with time

time1 = time2
time1 = x/10
time2 = (x+20)/14
(X/10)=(X+20)/14
we solve this to obation right answer

Manoj said:   1 decade ago
@Ilesh method is best one.


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