Aptitude - Time and Distance - Discussion

Most people have the confusion that time is equal has not been stated equal in the question, Then, how can we equate the two entities based on the assuption that time is equal, right?


Let me explain;
if t=1st hour, distance=10...also, distance=14
t=2nd hour, distance=20...also distance=14+14=28
..
.
Similarly when t=5th hour, distance=50...distance=70
Now, the difference in respective distances =70-50=20
This means that the distance covered is 20 more in the 5th hour when speed is 14kmph instead of 10kmph.
This means, in the same time, the distance covered is different(i.e. 20km more->as stated in the question)
This proves that the time interval is the same irrespective of speed is different.
So, we equated the two statements since the time taken has to be the same. Hope you got it.

Please give express that how to make this equation ?

It goes by the formula S=D/T (Speed = Distance/Time)

So, T = D/S => T=x/10 ............(1)

T = x+20/14 .........(2)

Taking both the times together we get frm (1) and (2)

x/10=x+20/14

Now solve it as shown above. Hope you get it now.

The persons speed of walking is 14km/hr.
He should have walked 10km/hr.
If he had gone with the speed of 10km/hr then he would have walked more den 20km/hr.
So,We are supposed to imagine if he had walked 10km/hr speed then what would be his actual speed.
So,we assume that let the distance be X km.


Then, the formula comes into picture i.e. speed=distance/time

So , as we are supposed to find as per the expectation if he had walked 10km/hr :
we take 10km/hr as his walking speed.
Distance is we are supposed to find more than 20
i.e. 20+X.
time is what the person actually doing .In reality the person is walking at 14km/hr.

So,in short with respect to person's capacity i.e. 14km/hr we can find the exact answer.
and therefore

Another formula for 10km/hr is :
time =distance by speed
i.e. time=X/10

time= X / 10 becomes the 1st equation....
time= (X + 20 ) / 14 becomes second equation....
from the above 2 eqns :
(X / 10 ) = (( X + 20 ) / 14)
then solve the further equation ....
Hope u got it :)

You have found the result for actual distance (i.e. x) and they said at 14km/he would walk 20km more. So we should do x+20(i.e. 50+20) right? We get 70km.

14x-10x=20,
4x=20,
X=5.
10*5=50km.

The Right answer is 70km.

Actually, he thinks that he needs to travel 10km/hr but he travelled 14km/hr.
In this case, he travelled extra 4km/hr, but finally, he travelled 20km extra.
So actual 50km+extra travelled 20km, total 70KM.

14km/hr - 10 km/hr = 4 km/hr(difference)
4km/hr - 20km,
10km/hr (?),
= 10*20/4.
= 50km.

Instead of 10 kmph he is walking 14kmph which means he is walking 4 kmph more and totally he walks 20 km.

Hence, 20/4=5.

If we take this for 10 kmph then x it by 5 which means 5* 50= 50kmph.

Can anyone tell me whether we can solve it like this?

Thanks @Kinnari.