Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
Then, | x | = | x + 20 |
10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
171 comments Page 13 of 18.
Bimal limbu said:
6 years ago
70 is the answer.
Sneha said:
6 years ago
You have found the result for actual distance (i.e. x) and they said at 14km/he would walk 20km more. So we should do x+20(i.e. 50+20) right? We get 70km.
(1)
Jinia siga said:
5 years ago
I do not understand why x+20 has taken in solution?
Kamal said:
5 years ago
Present speed = 14 km/h & Regular speed =10 km/h.
Difference of speed =14- 10 km/h = 4 km/h.
That means;
If his speed more 4 km/h he completes 20 km.
If he runs at his usual he complete = 20/5) * 10 km = 50 km.
Difference of speed =14- 10 km/h = 4 km/h.
That means;
If his speed more 4 km/h he completes 20 km.
If he runs at his usual he complete = 20/5) * 10 km = 50 km.
Amit said:
5 years ago
The correct answer should be 70 as the value of x is 50 at the speed of 10 km/hr but at the speed of 14 km hr is 20 more.
Sirisha said:
5 years ago
14x-10x=20,
4x=20,
X=5.
10*5=50km.
4x=20,
X=5.
10*5=50km.
(1)
Mr.Dims said:
5 years ago
The Right answer is 70km.
Actually, he thinks that he needs to travel 10km/hr but he travelled 14km/hr.
In this case, he travelled extra 4km/hr, but finally, he travelled 20km extra.
So actual 50km+extra travelled 20km, total 70KM.
Actually, he thinks that he needs to travel 10km/hr but he travelled 14km/hr.
In this case, he travelled extra 4km/hr, but finally, he travelled 20km extra.
So actual 50km+extra travelled 20km, total 70KM.
(1)
VishnuGpd said:
5 years ago
A:B
14:10
7:5.
Difference is 2parts.
2part=20km{actual difference).
1part=10km.
Multiply B part that is 5*10=50.
14:10
7:5.
Difference is 2parts.
2part=20km{actual difference).
1part=10km.
Multiply B part that is 5*10=50.
Sagar said:
5 years ago
Hi, whenever the time is constant we can equate the distance ratio to speed ratio. That is 10/14 =x/x+20 then x=50.
Anu said:
5 years ago
Thanks all for the explanation.
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