Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
                   
                                       
                                3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
 
                                    Answer: Option
                                                    Explanation:
                                                Let the actual distance travelled be x km.
| Then, | x | = | x + 20 | 
| 10 | 14 | 
 14x = 10x + 200
 4x = 200
 x = 50 km.
Discussion:
174 comments Page 13 of 18.
                
                        Bimal limbu said: 
                         
                        6 years ago
                
                70 is the answer.
                
                        Sneha said: 
                         
                        6 years ago
                
                You have found the result for actual distance (i.e. x) and they said at 14km/he would walk 20km more. So we should do x+20(i.e. 50+20) right? We get 70km.
                
                     (1)
                
            
                        Jinia siga said: 
                         
                        6 years ago
                
                I do not understand why x+20 has taken in solution?
                
                        Kamal said: 
                         
                        6 years ago
                
                Present speed = 14 km/h & Regular speed =10 km/h.
Difference of speed =14- 10 km/h = 4 km/h.
That means;
If his speed more 4 km/h he completes 20 km.
If he runs at his usual he complete = 20/5) * 10 km = 50 km.
                Difference of speed =14- 10 km/h = 4 km/h.
That means;
If his speed more 4 km/h he completes 20 km.
If he runs at his usual he complete = 20/5) * 10 km = 50 km.
                        Amit said: 
                         
                        6 years ago
                
                The correct answer should be 70 as the value of x is 50 at the speed of 10 km/hr but at the speed of 14 km hr is 20 more.
                
                        Sirisha said: 
                         
                        6 years ago
                
                14x-10x=20,
4x=20,
X=5.
10*5=50km.
                4x=20,
X=5.
10*5=50km.
                     (1)
                
            
                        Mr.Dims said: 
                         
                        6 years ago
                
                The Right answer is 70km.
Actually, he thinks that he needs to travel 10km/hr but he travelled 14km/hr.
In this case, he travelled extra 4km/hr, but finally, he travelled 20km extra.
So actual 50km+extra travelled 20km, total 70KM.
                Actually, he thinks that he needs to travel 10km/hr but he travelled 14km/hr.
In this case, he travelled extra 4km/hr, but finally, he travelled 20km extra.
So actual 50km+extra travelled 20km, total 70KM.
                     (1)
                
            
                        VishnuGpd said: 
                         
                        6 years ago
                
                A:B
14:10
7:5.
Difference is 2parts.
2part=20km{actual difference).
1part=10km.
Multiply B part that is 5*10=50.
                14:10
7:5.
Difference is 2parts.
2part=20km{actual difference).
1part=10km.
Multiply B part that is 5*10=50.
                        Sagar said: 
                         
                        5 years ago
                
                Hi, whenever the time is constant we can equate the distance ratio to speed ratio. That is 10/14 =x/x+20 then x=50.
                
                        Anu said: 
                         
                        5 years ago
                
                Thanks all for the explanation.
                Post your comments here:
 
            
        Quick links
                            Quantitative Aptitude
                                    
                                    Verbal (English)
                                    
                                    Reasoning
                                    
                                Programming
                                    
                                    Interview
                                    
                                     Placement Papers