Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 3)
3.
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
Answer: Option
Explanation:
Let the actual distance travelled be x km.
| Then, | x | = | x + 20 |
| 10 | 14 |
14x = 10x + 200
4x = 200
x = 50 km.
Discussion:
171 comments Page 11 of 18.
Manish said:
8 years ago
If he travels xkm.
He would have travelled with the speed of 10km/hr. Thus time=>x10.
But he travels with 14km/hr and thus he travels extra 20km => x+20 km. Thus time=>x+20/14
Equating both,
X/10=x+20/14.
You will get 50.
He would have travelled with the speed of 10km/hr. Thus time=>x10.
But he travels with 14km/hr and thus he travels extra 20km => x+20 km. Thus time=>x+20/14
Equating both,
X/10=x+20/14.
You will get 50.
Vishnu said:
7 years ago
Hi, friends.
Here both times are equal for traveling x, and x+20 so x/10 =x+20/14.
Here both times are equal for traveling x, and x+20 so x/10 =x+20/14.
Manu M said:
7 years ago
@All.
The actual distance travelled is 70 Km instead of 50 km. If he travels in 10 Kph distance should be 50, but he walks at a speed of 14 kph. So the actual distance is 70 Kph. Please correct me if any corrections.
The actual distance travelled is 70 Km instead of 50 km. If he travels in 10 Kph distance should be 50, but he walks at a speed of 14 kph. So the actual distance is 70 Kph. Please correct me if any corrections.
Krishna sai thota said:
7 years ago
He walks 14k/h instead 10k/h.
So he covered 20km in 20÷(14-10)= 5 hr.
So, D= 10* 5 = 50 Km.
So he covered 20km in 20÷(14-10)= 5 hr.
So, D= 10* 5 = 50 Km.
Rakesh said:
7 years ago
Why did you take the same value in both cases? Please explain.
Reshma said:
7 years ago
I think the answer should be 70. Because the actual distance travld is 50+20=7.
Am I right?
Am I right?
Ani said:
7 years ago
Why not X/14= (x+20) /10?
Shivani k said:
7 years ago
The question says that if he travelled 14km/hr instead of 10km/hr he would cover 20km more so
(14 -10)= 4 km/hr.
Distance covered with speed of 4km/hr=20km.
1km/hr= 20/4,
= 5km.
Actual distance covered with 10km/hr.
10 * 5 =50 km.
(14 -10)= 4 km/hr.
Distance covered with speed of 4km/hr=20km.
1km/hr= 20/4,
= 5km.
Actual distance covered with 10km/hr.
10 * 5 =50 km.
Palani said:
7 years ago
Friends, we should first understand the concept.
The man walks at 10kmph covered certain distance X. Then man instead of walks at 14kmph covered certain distance X. So both are covering the distance x first. Then he will take an extra time to cover 20km.
The Time difference
D is=20km.
Formula=D = D[a/a-b].
=20(10/4)=50km.
The man walks at 10kmph covered certain distance X. Then man instead of walks at 14kmph covered certain distance X. So both are covering the distance x first. Then he will take an extra time to cover 20km.
The Time difference
D is=20km.
Formula=D = D[a/a-b].
=20(10/4)=50km.
Ramu Dhakal said:
7 years ago
Time = Distance/Speed.
For 10km/h,
T=D/S.
Let the actual distance be x.
Therefore T= x/10 -------> Eq 1
For 14km/h,
T=D/S
T= x+20/14 ------> Eq 2
By equation 1 and 2.
x/10=x+20/14,
x=50.
For 10km/h,
T=D/S.
Let the actual distance be x.
Therefore T= x/10 -------> Eq 1
For 14km/h,
T=D/S
T= x+20/14 ------> Eq 2
By equation 1 and 2.
x/10=x+20/14,
x=50.
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