Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 8)
8.
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
Answer: Option
Explanation:
Let the total number of shots be x. Then,
| Shots fired by A = | 5 | x |
| 8 |
| Shots fired by B = | 3 | x |
| 8 |
| Killing shots by A = | 1 | of | 5 | x | = | 5 | x |
| 3 | 8 | 24 |
| Shots missed by B = | 1 | of | 3 | x | = | 3 | x |
| 2 | 8 | 16 |
 |
3x | = 27 or x = |  |
27 x 16 |  |
= 144. |
| 16 | 3 |
| Birds killed by A = | 5x | = | |
5 | x 144 | |
= 30. |
| 24 | 24 |
Discussion:
40 comments Page 3 of 4.
Varsha said:
10 years ago
How it is mean while A has shot 54*? And why (5/3) =90 times please tell me any one?
Chetna said:
1 decade ago
How is the no. of failure shots equal to the no. of succeded shots.. i.e. 3x/18=27??
(1)
Deepak said:
1 decade ago
It is hard to understand how 5/8 and 3/8 comes please anyone can explain?
Dory said:
8 years ago
So if B kills once in 3 shots, miss shots by B = ( 1-(1/3) ) * (3x/8)?
Malay giri said:
8 years ago
A-27*5=135,
b-27*3=81,
a-b=135-81,
=54/3=18,
A-18*5=90,
A=90/3=30.
b-27*3=81,
a-b=135-81,
=54/3=18,
A-18*5=90,
A=90/3=30.
(1)
Srinivas said:
8 years ago
Detail explanation of above problem please give me.
Suriya said:
1 decade ago
Please anybody explain very simply. ? please help.
Ryan said:
9 years ago
Any other simple method to solve this problem?
Mufassil said:
3 years ago
Thanks for explaining the answer @Hary.
(2)
Sai said:
2 years ago
Can anyone please explain the question?
(7)
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