Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 8)
8.
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
Answer: Option
Explanation:
Let the total number of shots be x. Then,
| Shots fired by A = | 5 | x |
| 8 |
| Shots fired by B = | 3 | x |
| 8 |
| Killing shots by A = | 1 | of | 5 | x | = | 5 | x |
| 3 | 8 | 24 |
| Shots missed by B = | 1 | of | 3 | x | = | 3 | x |
| 2 | 8 | 16 |
 |
3x | = 27 or x = |  |
27 x 16 |  |
= 144. |
| 16 | 3 |
| Birds killed by A = | 5x | = | |
5 | x 144 | |
= 30. |
| 24 | 24 |
Discussion:
40 comments Page 2 of 4.
Arun Congo said:
6 years ago
If A Shoot 5, B will shoot 3.
Assume in 1 Minute A can shoot 5 and B can shoot 3.
A Scores 1 out of 3, B scores 1 out of 2.
In question, we have 27 fails for B.
So in 9 minutes, B shoots 54 and scores 27 and fails 27.
In 9 Minutes, A shoot 90 and scores 30 and fails 60.
Assume in 1 Minute A can shoot 5 and B can shoot 3.
A Scores 1 out of 3, B scores 1 out of 2.
In question, we have 27 fails for B.
So in 9 minutes, B shoots 54 and scores 27 and fails 27.
In 9 Minutes, A shoot 90 and scores 30 and fails 60.
(8)
Rahul said:
1 decade ago
It is given that if A fires 5 shots B fires only 3 times.
It is given that p(A)=1/3 and p(B)=1/2.
It is also given that A missed 27 times so he fired totally 54 times.
From the above we can calculate that totally A fired 90 times.
So total successful firings by A=90*1/3=30.
It is given that p(A)=1/3 and p(B)=1/2.
It is also given that A missed 27 times so he fired totally 54 times.
From the above we can calculate that totally A fired 90 times.
So total successful firings by A=90*1/3=30.
(1)
Promodit said:
1 decade ago
A kills 5 birds while b kills 3. And hit ratio of A and B is 3:2 resp. (given).
Now while B has missed 27, total he has shot 54 times. Meanwhile A has shot 54*(5/3)=90 times. Now dividing by hit ratio will give total birds killed. i.e. 90/3 = 30 (answer).
Now while B has missed 27, total he has shot 54 times. Meanwhile A has shot 54*(5/3)=90 times. Now dividing by hit ratio will give total birds killed. i.e. 90/3 = 30 (answer).
SMRITHI said:
9 years ago
A:B=5:3.
27 shots fired failed by B.
Probability that B succeeds is 1/2 so total shorts is 27 * 2 = 54.
A/B= 5/3.
Therefore A/54=5/3, hence total shorts of A = 90.
Probability that A hits = 1/3;
Therefore total shorts hit = 90 * 1/3 = 30.
27 shots fired failed by B.
Probability that B succeeds is 1/2 so total shorts is 27 * 2 = 54.
A/B= 5/3.
Therefore A/54=5/3, hence total shorts of A = 90.
Probability that A hits = 1/3;
Therefore total shorts hit = 90 * 1/3 = 30.
Irshad Ahmad Tawav said:
9 years ago
Let A and B be 5x, 3x.
If x = 1, A = 5 B = 3,
If x = 2, A = 10 B = 6,
3x = 54,
=> x = 18,
Total number of shots of A = 5x
= 5 * 18 = 90,
Number of succeeding shots of A = 1/3 * total shots of A
= 1/3 * 90 = 30.
If x = 1, A = 5 B = 3,
If x = 2, A = 10 B = 6,
3x = 54,
=> x = 18,
Total number of shots of A = 5x
= 5 * 18 = 90,
Number of succeeding shots of A = 1/3 * total shots of A
= 1/3 * 90 = 30.
Nabanita Sarkar said:
1 decade ago
When B shots 2 it missed 1.
So, when B missed 27 B shoots (27*2) = 54.
When B shoots 3 at the same time A shoots 5.
So, total shoots of A = (5/3)*54 = 5*18= 90.
When A shoots 3 it killed 1.
So, when A shoots 90 it killed = 90/3 = 30.
So, when B missed 27 B shoots (27*2) = 54.
When B shoots 3 at the same time A shoots 5.
So, total shoots of A = (5/3)*54 = 5*18= 90.
When A shoots 3 it killed 1.
So, when A shoots 90 it killed = 90/3 = 30.
Jas said:
9 years ago
Total shots = 8.
A = 5/8.
B = 3/8.
A succeed 3times in 5/8 shots = 5/24.
B failed 2 times in 3/8 shots = 3/16.
Let total shots = x
B's failed = 3x/16.
Given 3x/16 = 27, x= 144.
Sub in A 5x/24 --> 5x144/24 --> A=30.
A = 5/8.
B = 3/8.
A succeed 3times in 5/8 shots = 5/24.
B failed 2 times in 3/8 shots = 3/16.
Let total shots = x
B's failed = 3x/16.
Given 3x/16 = 27, x= 144.
Sub in A 5x/24 --> 5x144/24 --> A=30.
Franco said:
1 decade ago
No. of failure shots equal to the no. of succeded shots
because B suceeds once in 2 shots
so probability of success is 1/2
probability of failure 1-(probability of success) =>1-1/2 = 1/2
because B suceeds once in 2 shots
so probability of success is 1/2
probability of failure 1-(probability of success) =>1-1/2 = 1/2
Ganga said:
4 years ago
B missed 27 times. Hence, B fired,
27 * 2 = 54 shots.
Therefore, the number of shots fired by
A = (54/3)*5,
= 90.
Therefore, the number of birds killed by;
A = 90*(1/3),
= 30.
27 * 2 = 54 shots.
Therefore, the number of shots fired by
A = (54/3)*5,
= 90.
Therefore, the number of birds killed by;
A = 90*(1/3),
= 30.
(40)
Renitha said:
11 months ago
Total short by B = 2 * 27 = 54,
Total short by A = 5/3 * 57 ==>5*18==>90,
killed by A = 90/3==>30,
A killed 30 birds.
Total short by A = 5/3 * 57 ==>5*18==>90,
killed by A = 90/3==>30,
A killed 30 birds.
(9)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers