Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 8)
8.
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
Answer: Option
Explanation:
Let the total number of shots be x. Then,
Shots fired by A = | 5 | x |
8 |
Shots fired by B = | 3 | x |
8 |
Killing shots by A = | 1 | of | 5 | x | = | 5 | x |
3 | 8 | 24 |
Shots missed by B = | 1 | of | 3 | x | = | 3 | x |
2 | 8 | 16 |
![]() |
3x | = 27 or x = | ![]() |
27 x 16 | ![]() |
= 144. |
16 | 3 |
Birds killed by A = | 5x | = | ![]() |
5 | x 144 | ![]() |
= 30. |
24 | 24 |
Discussion:
40 comments Page 4 of 4.
Pollard said:
2 decades ago
Please anybody explain very simply..?
Taniya said:
8 years ago
Thanks for your explanation @Kajora.
Siva said:
8 years ago
Well explained, Thanks @Smrithi.
(1)
Kaviya said:
3 years ago
Thanks for explaining @Smirthi.
(3)
Richa said:
8 years ago
Good job @Kajora.
Saif said:
9 years ago
Thank you @Naddy.
Danish said:
8 years ago
Superb @Smrithi.
Sapna said:
7 years ago
Thanks @Sudip.
(1)
SAI RAM said:
8 years ago
Thank you all.
Sonu said:
2 years ago
Thanks @Sudip.
(1)
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