Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 9 of 14.
Rajaram said:
9 years ago
O A R
10 3.2 32
40 x 250 (282-32).
x = 250/40 = 6.25.
10 3.2 32
40 x 250 (282-32).
x = 250/40 = 6.25.
Masthan said:
5 years ago
10 * 3.2 = 32
40 * X = 282
=> 282 - 32 = 250.
40X = 250.
X = 250/40.
X = 6.25.
40 * X = 282
=> 282 - 32 = 250.
40X = 250.
X = 250/40.
X = 6.25.
(9)
Ritesh bajaj said:
9 years ago
Why we subtract 282 from (3.2*10) and why we divide the whole thing by 40?
Manoj said:
9 years ago
You have 2 candles each burn for 1 hour tell when the time is 45 minutes.
Dilepkumar said:
2 decades ago
They asking only remainig 40 over run rate. So why use of first 10 over?
Jay said:
1 decade ago
Thank you very much muhundhan. Simple answer to understand.
DKB said:
1 decade ago
Pratik and Muhundhan Thanks for simplifying the problem.
Mounika said:
8 years ago
Am not understanding this, Please explain in simple way.
Vinay said:
9 years ago
@Dilepkumar.
The game is of 50 overs is directly said.
The game is of 50 overs is directly said.
Ramya said:
1 decade ago
What is the actual formula for this type of questions?
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