Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
134 comments Page 10 of 14.
Kavita said:
2 decades ago
How do we arrive at the solution.? What is the logic?
Banita said:
1 decade ago
Excellent explanation Tarun and Deepa, Thanks a lot
Rituparna Sengupta said:
1 decade ago
Required run-rate = (282-(3.2*10))/40 = 6.25.
Kavya said:
8 years ago
Super & excellent explanation @Muhundhan.
Ahmed Raafat said:
2 years ago
Run rate = number of runs/number of overs.
(15)
Renu said:
9 years ago
Super & excellent explanation @Muhundhan.
Akshata said:
1 decade ago
Formula used for this type of questions?
Nayan das said:
1 decade ago
Very good explanation vinoth m, thanks.
BISWAJIT said:
7 years ago
Not understanding this, please explain.
Ganesh said:
7 years ago
3.2*10=32.
282-32=250.
250÷40=6.25.
282-32=250.
250÷40=6.25.
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