Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 1)
1.
In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Answer: Option
Explanation:
| Required run rate = |  |
282 - (3.2 x 10) |  |
= | 250 | = 6.25 |
| 40 | 40 |
Video Explanation: https://youtu.be/GhK9d8tcqvA
Discussion:
137 comments Page 11 of 14.
Nayan das said:
1 decade ago
Very good explanation vinoth m, thanks.
BISWAJIT said:
8 years ago
Not understanding this, please explain.
Ganesh said:
8 years ago
3.2*10=32.
282-32=250.
250÷40=6.25.
282-32=250.
250÷40=6.25.
Raj said:
1 decade ago
10*3.2 = 32.
40*? = ?
Required = 282.
40*? = ?
Required = 282.
Soudri said:
1 decade ago
10*3.2=32
So 282 - 32 = 250/40= 6.25
So 282 - 32 = 250/40= 6.25
Sonu kumar sharma said:
10 years ago
You all explained very well thanks.
Ram said:
8 years ago
Thanks for the explanation @Deepa.
Deebika.c said:
1 decade ago
What is the formula for this sum?
Ranjith said:
2 decades ago
Why do we minus 282-(3.2*10)...?
Swetha said:
2 decades ago
Why are you minus that 282 runs?
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